8–8 ■ EXERGY BALANCE: CONTROL VOLUMES
The exergy balance relations for control volumes differ from those for closed
systems in that they involve one more mechanism of exergy transfer:mass flow
across the boundaries.As mentioned earlier, mass possesses exergy as well as
energy and entropy, and the amounts of these three extensive properties are
Chapter 8 | 457since KE PE 0 and U0 (the change in internal energy of an ideal
gas is zero during an isothermal process), and SsysQ/Tsysfor isothermal
processes in the absence of any irreversibilities. Then,Therefore, the useful work output would be 2.65 kJ instead of 1.43 kJ if the
process were executed in a totally reversible manner.
Alternative Approach The reversible work could also be determined by apply-
ing the basics only, without resorting to exergy balance. This is done by
replacing the irreversible portions of the process by reversible ones that cre-
ate the same effect on the system. The useful work output of this idealized
process (between the actual end states) is the reversible work.
The only irreversibility the actual process involves is the heat transfer
between the system and the furnace through a finite temperature difference.
This irreversibility can be eliminated by operating a reversible heat engine
between the furnace at 1200 K and the surroundings at 300 K. When 2.43
kJ of heat is supplied to this heat engine, it produces a work output ofThe 2.43 kJ of heat that was transferred to the system from the source is
now extracted from the surrounding air at 300 K by a reversible heat pump
that requires a work input ofThen the net work output of this reversible process (i.e., the reversible work)
becomeswhich is practically identical to the result obtained before. Also, the exergy
destroyed is the difference between the reversible work and the useful work,
and is determined to bewhich is identical to the result obtained before.XdestroyedWrev,outWu,out2.651.431.22 kJWrevWuWHEWHP,in1.431.820.612.64 kJWHP,inQH
COPHPcQH
TH>1THTL 2d
HP2.43 kJ
1 400 K2>3 1 400 3002 K 40.61 kJWHEhrevQHa 1 TL
THbQHa 1 300 K
1200 Kb12.43 kJ 2 1.82 kJ 2.65 kJ 1 300 K 22.43 kJ
400 K 1 1 kJ 2 a 1 300 K
1200 Kb12.43 kJ 2Wrev,outT 0Q
TsysWsurra 1 T 0
TRbQSEE TUTORIAL CH. 8, SEC. 8 ON THE DVD.INTERACTIVE
TUTORIAL