remaining part of the energy released shows up as the kinetic energy of the
exhaust gases relative to a fixed point on the ground and as an increase in
the enthalpy of the gases leaving the engine.
Chapter 9 | 523
EXAMPLE 9–9 The Ideal Jet-Propulsion Cycle
A turbojet aircraft flies with a velocity of 850 ft/s at an altitude where the air is
at 5 psia and 40°F. The compressor has a pressure ratio of 10, and the tem-
perature of the gases at the turbine inlet is 2000°F. Air enters the compressor
at a rate of 100 lbm/s. Utilizing the cold-air-standard assumptions, determine
(a) the temperature and pressure of the gases at the turbine exit, (b) the veloc-
ity of the gases at the nozzle exit, and (c) the propulsive efficiency of the cycle.
Solution The operating conditions of a turbojet aircraft are specified. The
temperature and pressure at the turbine exit, the velocity of gases at the
nozzle exit, and the propulsive efficiency are to be determined.
Assumptions 1 Steady operating conditions exist. 2 The cold-air-standard
assumptions are applicable and thus air can be assumed to have constant
specific heats at room temperature (cp0.240 Btu/lbm · °F and k1.4).
3 Kinetic and potential energies are negligible, except at the diffuser inlet
and the nozzle exit. 4 The turbine work output is equal to the compressor
work input.
Analysis The T-sdiagram of the ideal jet propulsion cycle described is shown
in Fig. 9–50. We note that the components involved in the jet-propulsion
cycle are steady-flow devices.
(a) Before we can determine the temperature and pressure at the turbine
exit, we need to find the temperatures and pressures at other states:
Process 1-2(isentropic compression of an ideal gas in a diffuser): For con-
venience, we can assume that the aircraft is stationary and the air is moving
toward the aircraft at a velocity of V 1 850 ft/s. Ideally, the air exits the
diffuser with a negligible velocity (V 2 0):
Process 2-3(isentropic compression of an ideal gas in a compressor):
T 3 T 2 a
P 3
P 2
b
1 k 1 2>k
1 480 R 211021 1.4^1 2>1.4927 R
P 3 1 rp 21 P 22 11021 8.0 psia 2 80 psia 1 P 42
P 2 P 1 a
T 2
T 1
b
k>1k 12
1 5 psia2a
480 R
420 R
b
1.4>11.4 12
8.0 psia
480 R
420 R
1 850 ft>s 22
21 0.240 Btu>lbm#R 2
a
1 Btu>lbm
25,037 ft^2 >s^2
b
T 2 T 1
V^21
2 cp
0 cp 1 T 2 T 12
V 12
2
h 2
V 22
2
h 1
V^21
2
P = const.
P = const.
s
T, °F
qin
qout
6
5
4
3
2
2000
–40 1
FIGURE 9–50
T-sdiagram for the turbojet cycle
described in Example 9–9.
0
¡