Solutions
- $GHFDJRQKDVVLGHV2QHDFKVLGHRIWKH¿JXUHGUDZDWULDQJOH
with apex at the center of the decagon, as shown in Figure S.21.7.
With the labels given, we see that tan x (^1) a, giving a (^) tan^1 x.
Now, 2x is 101 of a full turn, so 2 x 36010 36.
Thus, x = 18°, a (^) tan 18° 1 , and
area = 10 u^1122 aa (^1010) tan 18 |30.8.
- Dͽ 6HHFigure S.21.8.
The triangle on the left is half an equilateral triangle
ͼWKHPLUURUKDOILVEHORZLWͽ
Thus, h = 1. Using Example 1 from the lesson for
WKHDUHDRIDSDUDOOHORJUDPZHKDYHDUHD î
Eͽ 6HHFigure S.21.9.
hh ^22 DQG DUHD ^12
Fͽ ^2 + 35^2 = 37^2 :HKDYHDULJKWWULDQJOH6HHFigure S.21.10ͽ
Area =^12 u 12 35 210.
Gͽ 6HHFigure S.21.11.
Area = u^12 - Dͽ 6HHFigure S.21.12.
x^2 + x^2 = 7^2 , so x 72.
Thus, area = 22.
a
(^11)
x
Figure S.21.7
30°
(^22)
4
4
h
Figure S.21.8
10 10
8
h
Figure S.21.9
(^1235)
37
Figure S.21.10
Figure S.21.11
4
4
3
3
55
5
5
x
x
7
Figure S.21.12