Quantum Mechanics for Mathematicians

(lily) #1
The Dirac equation

(γ 0


∂x 0

+γ·∇−m)ψ(x) = 0

can be written in the form of a Schr ̈odinger equation as


i


∂t

ψ(t,x) =HDψ(t,x) (47.4)

with Hamiltonian
HD=iγ 0 (γ·∇−m) (47.5)


Fourier transforming, in momentum space the energy eigenvalue equation is


−γ 0 (γ·p+im)ψ ̃(p) =Eψ ̃(p)

The square of the left-hand side of this equation is


(−γ 0 (γ·p+im))^2 =γ 0 (γ·p+im)γ 0 (γ·p+im)
=(γ·p−im)(γ·p+im)
=(γ·p)^2 +m^2 =|p|^2 +m^2

This shows that solutions to the Dirac equation have the expected relativistic
energy-momentum relation


E=±ωp=±


|p|^2 +m^2

For eachp, there will be a two dimensional space of solutionsψ ̃+(p) to

−γ 0 (γ·p+im)ψ ̃+(p) =ωpψ ̃+(p) (47.6)

(the positive energy solutions), and a two dimensional space of solutionsψ ̃−(p)
to
−γ 0 (γ·p+im)ψ ̃−(p) =−ωpψ ̃−(p) (47.7)


(the negative energy solutions). Solutions to the Dirac equation can be identified
with either



  • Four-component functionsψ(x), initial value data at a timet= 0.

  • Four-component functionsψ ̃(p), Fourier transforms of the initial value
    data. These can be decomposed as


ψ ̃(p) =ψ ̃+(p) +ψ ̃−(p) (47.8)

into positive (solutions of 47.6) and negative (solutions of 47.7) energy
components.
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