DHARM518 GEOTECHNICAL ENGINEERINGTotal active thrust per lineal metre of wall,Pa = Area of pressure distribution diagram =1
2KH KqH^2
aaγ+=1
2××+×= +59 9 6 3 23 8 6 3 188 7 149 9.. .... = 338.6 kNThe height of its point of application above the base may be obtained by taking mo-
ments:z =188 7^1
36 3 149 9^1
263338 6.....F ×× + ××
HGI
KJ
m = 2.56 mExample 13.6: A vertical wall with a smooth face is 7.2 m high and retains soil with a uniform
surcharge angle of 9°. If the angle of internal friction of soil is 27°, compute the active earth
pressure and passive earth resistance assuming γ = 20 kN/m^3
H = 7.2 m β = 9°
φ = 27° γ = 20 kN/m^32.4 m7.2 m PorPapWall9°b=9°Fig. 13.55 Retaining wall with inclined surcharge
and pressure distribution (Ex. 13.6)
According to Rankine’s theory,Ka = coscos cos cos
cos cos cosβββφ
ββφ−−
+−F
H
G
GI
K
J
J22
22= coscos cos cos
cos cos cos99927
992722
22°°− °− °
°+ °− °F
H
G
GI
K
J
J= 0.988 × 0.397 = 0.392Kp = coscos cos cos
cos cos cos.
.βββφ
ββφ+−
−−F
H
G
GI
K
J
J=×22
220 988^1
0 397 = 2.488Total active thrust per metre run of the wallPa =1
21
2γHK^22 .(a=× × 20 7 2.).×0 392 = 203.2 kN