DHARMLATERAL EARTH PRESSURE AND STABILITY OF RETAINING WALLS 519Total passive resistance per metre run of the wallPp =1
21
2γHK^22 .(p=× × 20 7 2.).×2 488 = 1289.8 kNThe pressure is considered to act parallel to the surface of the backfill soil and the
distribution is triangular for both cases. This resultant thrust thus acts at a height of (1/3) H or
2.4 m above the base at 9° to horizontal, as shown in Fig. 13.55.
Example 13.7: The Rankine formula of active earth pressure for a vertical wall and a level fill
is much better known than the general form and sometimes it is used even when it does not
apply. Determine the percentage error introduced by assuming a level fill when the angle of
surcharge actually equals 20°. Assume a friction angle of 35° and the wall vertical. Comment
of the use of the erroneous result. (S.V.U.—B.E. (R.R.)—Nov., 1974)
φ = 35°
Active pressure coefficient of Rankine for inclined surcharge:Kai = cos.cos cos cos
cos cos cosβββφ
ββφ−−
+−F
H
G
GI
K
J
J22
22when β = 0° for horizontal surface of the backfill,Ka =1
1−
+sin
sinφ
φ
Kai for β = 20° and φ = 35° is given byKai = coscos cos cos
cos cos cos2020 20 35
20 20 3522
° 22°− °− °
°+ °− °F
H
G
GI
K
J
J = 0.322Ka for β = 0° and φ = 35° is given byKa =135
1350 271−°
+°=sin
sin.Percentage error in the computed active thrust by assuming a level fill when it is actu-
ally inclined at 20° to horizontal=0 322 0 271
0 322.. 100
.F −
HGI
KJ× = 15.84The thrust is understimated by assuming a level fill, obviously.
Example 13.8: A retaining wall 9 m high retains a cohesionless soil, with an angle of internal
friction 33°. The surface is level with the top of the wall. The unit weight of the top 3 m of the
fill is 21 kN/m^3 and that of the rest is 27 kN/m^3. Find the magnitude and point of application of
the resultant active thrust.
It is assumed that φ = 33° for both the strata of the backfill.