DHARM
LATERAL EARTH PRESSURE AND STABILITY OF RETAINING WALLS 519
Total passive resistance per metre run of the wall
Pp =
1
2
1
2
γHK^22 .(p=× × 20 7 2.).×2 488 = 1289.8 kN
The pressure is considered to act parallel to the surface of the backfill soil and the
distribution is triangular for both cases. This resultant thrust thus acts at a height of (1/3) H or
2.4 m above the base at 9° to horizontal, as shown in Fig. 13.55.
Example 13.7: The Rankine formula of active earth pressure for a vertical wall and a level fill
is much better known than the general form and sometimes it is used even when it does not
apply. Determine the percentage error introduced by assuming a level fill when the angle of
surcharge actually equals 20°. Assume a friction angle of 35° and the wall vertical. Comment
of the use of the erroneous result. (S.V.U.—B.E. (R.R.)—Nov., 1974)
φ = 35°
Active pressure coefficient of Rankine for inclined surcharge:
Kai = cos.
cos cos cos
cos cos cos
β
ββφ
ββφ
−−
+−
F
H
G
G
I
K
J
J
22
22
when β = 0° for horizontal surface of the backfill,
Ka =
1
1
−
+
sin
sin
φ
φ
Kai for β = 20° and φ = 35° is given by
Kai = cos
cos cos cos
cos cos cos
20
20 20 35
20 20 35
22
° 22
°− °− °
°+ °− °
F
H
G
G
I
K
J
J = 0.322
Ka for β = 0° and φ = 35° is given by
Ka =
135
135
0 271
−°
+°
=
sin
sin
.
Percentage error in the computed active thrust by assuming a level fill when it is actu-
ally inclined at 20° to horizontal
=
0 322 0 271
0 322
.. 100
.
F −
HG
I
KJ
× = 15.84
The thrust is understimated by assuming a level fill, obviously.
Example 13.8: A retaining wall 9 m high retains a cohesionless soil, with an angle of internal
friction 33°. The surface is level with the top of the wall. The unit weight of the top 3 m of the
fill is 21 kN/m^3 and that of the rest is 27 kN/m^3. Find the magnitude and point of application of
the resultant active thrust.
It is assumed that φ = 33° for both the strata of the backfill.