486 13 Stability of Elastic SystemsThus, differential equation (13.13a) becomesd^2 w
d^2C
1 CqR^3
EI
wDk'
EIR^2
sin ̨sin: (13.15)Denoten^2 D 1 CqR^3
EI: (13.15a)CDk' R^2
EIsin ̨: (13.15b)Pay attention thatCis unknown, since the angles of rotation'of the supports are
unknown. Differential equation (13.15) may be rewritten as followsd^2 w
d^2Cn^2 wDCsin: (13.16)Solution of this equation iswDAcosnCBsinnCw: (13.17)The partial solutionwshould be presented in the form of the right part of (13.16),
mainlywDC 0 sin,whereC 0 is a new unknown coefficient. Substituting of this
expression into (13.16) leads to equationC 0 sinCn^2 C 0 sinDCsin;so
C 0 DC
n^2 1:Thus the solution of equation (13.15) becomeswDAcosnCBsinnCC
n^2 1sin: (13.17a)Unknown coefficientsA, B,andCmay be obtained from the following boundary
conditions:1.For point of the arch on the axis of symmetry.D0/, the radial displacement
wD 0 (because the antisymmetrical form ofthe loss of stability); this condition
leads toAD 0 ;
2.For point of the arch at the support.D ̨/the radial displacement iswD 0 ,so
Bsinn ̨CC
n^2 1sin ̨D0: (13.18)