162 Higher Engineering Mathematics
- cosAsinB=
1
2[sin(A+B)−sin(A−B)]
⎡
⎢
⎣coshθcoshφ=1
2[sinh(θ+φ)−sinh(θ−φ)]⎤
⎥
⎦- sin^3 A=
3
4sinA−1
4sin3A
[
sinh^3 θ=1
4sinh3θ−3
4sinhθ]- cot^2 A(sec^2 A− 1 )= 1
[coth^2 θ( 1 −sech^2 θ)=1]
162 Higher Engineering Mathematics
1
2[sin(A+B)−sin(A−B)]
⎡
⎢
⎣coshθcoshφ=1
2[sinh(θ+φ)−sinh(θ−φ)]⎤
⎥
⎦3
4sinA−1
4sin3A
[
sinh^3 θ=1
4sinh3θ−3
4sinhθ]