Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

664 Higher Engineering Mathematics


yorf(x)

dy
dx

orf′(x)

cos−^1 f(x)

−f′(x)

1 −[f(x)]^2

tan−^1

x
a

a
a^2 +x^2

tan−^1 f(x)

f′(x)
1 +[f(x)]^2

sec−^1

x
a

a
x


x^2 −a^2

sec−^1 f(x)

f′(x)
f(x)


[f(x)]^2 − 1

cosec−^1

x
a

−a
x


x^2 −a^2

cosec−^1 f(x)

−f′(x)
f(x)


[f(x)]^2 − 1

cot−^1

x
a

−a
a^2 +x^2

cot−^1 f(x)

−f′(x)
1 +[f(x)]^2

sinh−^1

x
a

1

x^2 +a^2

sinh−^1 f(x)

f′(x)

[f(x)]^2 + 1

cosh−^1

x
a

1

x^2 −a^2

cosh−^1 f(x)

f′(x)

[f(x)]^2 − 1

tanh−^1

x
a

a
a^2 −x^2

tanh−^1 f(x)

f′(x)
1 −[f(x)]^2

sech−^1

x
a

−a
x


a^2 −x^2

sech−^1 f(x)

−f′(x)
f(x)


1 −[f(x)]^2

yorf(x)

dy
dx

orf′(x)

cosech−^1

x
a

−a
x


x^2 +a^2

cosech−^1 f(x)

−f′(x)
f(x)


[f(x)]^2 + 1

coth−^1

x
a

a
a^2 −x^2

coth−^1 f(x)

f′(x)
1 −[f(x)]^2

Product rule:


Wheny=uvanduandvare functions ofxthen:
dy
dx

=u

dv
dx

+v

du
dx

Quotient rule:


Wheny=

u
v

anduandvare functions ofxthen:

dy
dx

=

v

du
dx

−u

dv
dx
v^2

Function of a function:


Ifuis a function ofxthen:
dy
dx

=

dy
du

×

du
dx

Parametric differentiation:


Ifxandyare both functions ofθ, then:

dy
dx

=

dy

dx

and

d^2 y
dx^2

=

d

(
dy
dx

)

dx

Implicit function:


d
dx

[f(y)]=

d
dy

[f(y)]×

dy
dx
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