7—Operators and Matrices 176
The rotated~e 1 has two components, so
Rα(~e 1 ) =~e 1 cosα+~e 2 sinα=R 11 ~e 1 +R 21 ~e 2
This determines the first column of the matrix of components,
R 11 = cosα, and R 21 = sinα
Similarly the effect on the other basis vector determines the second column:
Rα(~e 2 ) =~e 2 cosα−~e 1 sinα=R 12 ~e 1 +R 22 ~e 2
Check:Rα(~e 1 ).Rα(~e 2 ) = 0.
R 12 =−sinα, and R 22 = cosα
The component matrix is then
(
Rα
)
=
(
cosα −sinα
sinα cosα
)
(11)
Components of Inertia
The definition, Eq. ( 3 ), and the figure preceding it specify the inertia tensor as the function that relates the
angular momentum of a rigid body to its angular velocity.
~L=
∫
dm~r×
(
~ω×~r
)
=I(~ω) (12)
Use the vector identity,
A~×(B~×C~) =B~(A~.C~)−C~(A~.B~) (13)
then the integral is
L~=
∫
dm
[
~ω(~r.~r)−~r(~ω.~r)
]
=I(~ω)