Hardy-Weinberg Equilibrium Part 2
If we mate two individuals that are
heterozygous (e.g., Bb) for a trait what will
we find? (Let’s make the punnet square).
Look at that. In this group our resulting
offspring will be:
1 BB,
2 Bb,
1 bb
This means that:
25% of their offspring are homozygous for the
dominant allele (BB).
50% are heterozygous like their parents (Bb)
and
25% are homozygous for the recessive allele
(bb).
Now look at this closely. Unlike their
parents Bb Bb, 25% will express the recessive
(^) B b
B BB Bb
b Bb bb