11.6
11.7
11.8
11.9
11.10
11.11
11.12
11.13
11.14 221 2222
x
Ne x
x x
αα⎛ α
⎝⎜⎜
⎞
⎠
⎟⎟
⎛
⎝
⎜⎜
⎞
⎠
− ⎟⎟
−∞+∞
∫ ()()
/ (()Nex/ x
1
−^222 α d()()()Ne 0 −xx^22 //^22 x Ne 0 222 x
−∞+∞
−
∫
ααdDO2Hμλ= ...λ 2 O×
===
16 2
18
mmHH 178 138 4 11 μmHO
HO /
DOHO
216 1
17
094 2
2μ ω^2
ωμ
=.×
mm==k
HH kk/
μDO 2178
094
138
.
.
=.
Peyey==//yy∞
−−∞
∫∫11
12
1
12
122
απα
πddν
ν2 21
2
m
mkm
km==
/
/
A== −
ν
c1087 cm^1ν
πμ π.==.
×
=
−
−1
2
1
2
500
119 10
326
1
26k Nm
kg× 1013 s−^1μ=.
+=
×
+
=×
mm
mmCO m
COp13 16
13 16
119 10 0 −^26 kgA== −
ν
c1111 cm^1ν
πμ π.==.
×
=
−
−1
2
1
2
500
114 10
333
1
26k Nm
kg× 1013 s−^1μ=.
+=
×
+
=×
mm
mmCO m
COp12 16
12 16
114 10−^26 kgν
π.=.
×
=×
−
−(^1) −
2
600
167 10
95 10
1
27Nm 13
kgs^11μ=.
+=
×
+
=×
mm
mmCO m
COp13 16
13 16
119 10−^26 kgANSWERS TO PROBLEMS 463
9781405124362_5_end.qxd 4/29/08 9:17 Page 463