Cake eating problem
It is easy to see that
c 1 =
w 1
1 +β+.. .+βT ^1
,
c 2 = βw^1
1 +β+.. .+βT ^1
,
..
.
cT = β
T (^1) w 1
1 +β+.. .+βT ^1
is a stationary point. As the problem is convex, it is the optimal solution.
It is easy to see that
c 1 =
w 1
1 +β+.. .+βT ^1
c 2 = βw^1
1 +β+.. .+βT ^1
cT = β
T (^1) w 1
1 +β+.. .+βT ^1
is a stationary point. As the problem is convex, it is the optimal solution.