62 4 Eigen Values and VectorsAi = 1.0, A 2 = 0.94 =>• V! , V 2SAS'^1 =|1
-1 11.00Vk
Zk0.95 0.01
0.05 0.99-ik
|1
-1 10.941.00*-1
5 5
5 _I
6 60.94*/5 5
= ^2/o + ^oSince 0.94* -» 0 as A; -)• oo,+ I |»b " ^o ) 0.94*I I
I -I
1
-12/oo
•2 CO
= l^2/o + |«b L6 6 JTVie steady-state probabilities are computed as in the classical way, Auoo —
1 • Moo, corresponding to the eigen value of one. Thus, the steady-state vector
is the eigen vector of A corresponding to A = 1, after normalization to have
legitimate probabilities (see Remark 4-3-4):Moo = avi = -^5 [I
6" 1 '
5
L J^1" 1 "
6
5
64.4.2 Differential Equations
Example 4.4.7
du
~dlAu •
23
14
u <=> u(t) = eAtu 0 -Xx = 5,vi = (l,lf, A 2 = l, «2 = (-3,l)au(t) = a 1 eAlS 1 + a 2 e*2tv 2 = axe „5tU 0 = «1 + a 2u(t) 1 -3
1 1a5t-3
1OLi1
1
1 -3
1 1+ a 2 etOil-3
1= SJ>t
5-^0-The power series expansion of the exponentiation of one scalar is