62 4 Eigen Values and Vectors
Ai = 1.0, A 2 = 0.94 =>• V! , V 2
SAS'^1 =
|1
-1 1
1.00
Vk
Zk
0.95 0.01
0.05 0.99
-ik
|1
-1 1
0.94
1.00*
-1
5 5
5 _I
6 6
0.94*
/5 5
= ^2/o + ^o
Since 0.94* -» 0 as A; -)• oo,
+ I |»b " ^o ) 0.94*
I I
I -I
1
-1
2/oo
•2 CO
= l^2/o + |«b L6 6 J
TVie steady-state probabilities are computed as in the classical way, Auoo —
1 • Moo, corresponding to the eigen value of one. Thus, the steady-state vector
is the eigen vector of A corresponding to A = 1, after normalization to have
legitimate probabilities (see Remark 4-3-4):
Moo = avi = -^5 [I
6
" 1 '
5
L J^1
" 1 "
6
5
6
4.4.2 Differential Equations
Example 4.4.7
du
~dl
Au •
23
14
u <=> u(t) = eAtu 0 -
Xx = 5,vi = (l,lf, A 2 = l, «2 = (-3,l)a
u(t) = a 1 eAlS 1 + a 2 e*2tv 2 = axe „5t
U 0 = «1 + a 2
u(t) 1 -3
1 1
a5t
-3
1
OLi
1
1
1 -3
1 1
+ a 2 et
Oil
-3
1
= S
J>t
5-^0-
The power series expansion of the exponentiation of one scalar is