184 5. Further Determinant Theory
=Hnn+1−j
∑s=1ψ 2 n−sδs,n−j+1=Hnψn+j− 1 , 1 ≤j≤n; (5.2.21)Yi=n
∑j=1K
(n)
jn2 n−i−j+1
∑s=n+2−jφt+i+2ψ 2 n−s,[
s=t−js→t]
=
n
∑j=1K
(n)
jn2 n−i+1
∑t=n+2φt+i− 2 ψ 2 n+j−t=
2 n−i+1
∑t=n+2φt+i− 2n
∑j=1ψ 2 n+j−tK(n)
jn=
2 n−i+1
∑t=n+2φt+i− 2n
∑j=1kj+n+1−t,nK(n)
jn=Kn2 n−i+1
∑t=n+2φt+i− 2 δt,n+1=0, 1 ≤i≤n− 1 , (5.2.22)sincet>n+ 1. Hence,
Pfn=Hnn
∑j=1K
(n)
jn
ψn+j− 1=Hnn
∑j=1kjnK(n)
jn=HnKn,which completes the proof of Theorem 5.1.
5.2.4 Three Further Theorems
The principal theorem, when expressed in the form
2 n− 1
∑i=1(−1)
i+1
Pf(n)
i
ai, 2 n=HnKn, (5.2.23)yields two corollaries by partial differentiation. Since the only elements
in Pfnwhich containφ 2 n− 1 andψ 2 n− 1 areai, 2 n,1≤i≤ 2 n−1, and
Pf
(n)
i
is independent ofai, 2 n, it follows that Pf(n)
i
is independent ofφ 2 n− 1andψ 2 n− 1. Moreover, these two functions occur only once inHnandKn,
respectively, both in position (n, n).