5.10 The Reciprocal Theorem 155
Fig.5.28
Model analysis of a fixed beam.
or
θA(c),2=
W
M
δ 1 (ii)
whereθA(c),2is the rotation at A due toWat C. Finally, the rotation at A due toMAat A is, from
Fig.5.28(a)and(c),
θA(c),3=
MA
M
θA (iii)
ThetotalrotationatAproducedbyMAatA,WatC,andMBatBis,fromEqs.(i),(ii),and(iii),
θA(c),1+θA(c),2+θA(c),3=
MB
M
θB+
W
M
δ 1 +
MA
M
θA=0(iv)
sincetheendAisrestrainedfromrotation.Similarly,therotationatBisgivenby
MB
M
θC+
W
M
δ 2 +
MA
M
θB=0(v)
SolvingEqs.(iv)and(v)forMAgives
MA=W
(
δ 2 θB−δ 1 θC
θAθC−θB^2
)
ThefactthatthearbitrarymomentMdoesnotappearintheexpressionfortherestrainingmoment
at A (similarly it does not appear inMB), produced by the loadW, indicates an extremely useful
applicationofthereciprocaltheorem,namelythemodelanalysisofstaticallyindeterminatestructures.
Forexample,thefixedbeamofFig.5.28(c)couldpossiblybeafull-scalebridgegirder.Itisthenonly
necessary to construct a model, say of Perspex, having the same flexural rigidityEIas the full-scale
beam and measure rotations and displacements produced by an arbitrary momentMto obtain fixing
momentsinthefull-scalebeamsupportingafull-scaleload.