16.2 Shear of Open Section Beams 487
Fig.16.8
Shear center position for type of open section beam shown.
Fig.16.9
Determination of shear center position of channel section of Example 16.2.
TheshearcenterSliesonthehorizontalaxisofsymmetryatsomedistanceξS,say,fromtheweb.
IfweapplyanarbitraryshearloadSythroughtheshearcenter,thentheshearflowdistributionisgiven
byEq.(16.14)andthemomentaboutanypointinthecrosssectionproducedbytheseshearflowsis
equivalenttothemomentoftheappliedshearload.Syappearsonbothsidesoftheresultingequation
andmaythereforebeeliminatedtoleaveξS.
Forthechannelsection,CxisanaxisofsymmetrysothatIxy=0.AlsoSx=0andthereforeEq.(16.14)
simplifiesto
qs=−
Sy
Ixx
∫s
0
tyds (i)
where
Ixx= 2 bt
(
h
2
) 2
+
th^3
12
=
h^3 t
12
(
1 +
6 b
h