68 CHAPTER 3 Torsion of Solid Sections
Thus,φisconstantonthesurfaceofthebar,andsincetheactualvalueofthisconstantdoesnotaffect
thestressesofEq.(3.2),wemayconvenientlytaketheconstanttobezero.Hence,onthecylindrical
surfaceofthebar,wehavetheboundarycondition
φ= 0 (3.7)
Ontheendsofthebar,thedirectioncosinesofthenormaltothesurfacehavethevaluesl=0,m=0,
andn=1.Therelatedboundaryconditions,fromEqs.(1.7),arethen
X=τzx
Y=τzy
Z= 0
Wenowobservethattheforcesoneachendofthebarareshearforceswhicharedistributedoverthe
ends of the bar in the same manner as the shear stresses are distributed over the cross section. The
resultantshearforceinthepositivedirectionofthexaxis,whichweshallcallSx,isthen
Sx=
∫∫
Xdxdy=
∫∫
τzxdxdy
or,usingtherelationshipofEqs.(3.2),
Sx=
∫∫
∂φ
∂y
dxdy=
∫
dx
∫
∂φ
∂y
dy= 0
asφ=0attheboundary.Inasimilarmanner,Sy,theresultantshearforceintheydirection,is
Sy=−
∫
dy
∫
∂φ
∂x
dx= 0
Itfollowsthatthereisnoresultantshearforceontheendsofthebarandtheforcesrepresentatorque
ofmagnitude,referringtoFig.3.3
T=
∫∫
(τzyx−τzxy)dxdy
inwhichwetakethesignofTasbeingpositiveintheanticlockwisesense.
Rewritingthisequationintermsofthestressfunctionφ
T=−
∫∫
∂φ
∂x
xdxdy−
∫∫
∂φ
∂y
ydxdy
Integratingeachtermontheright-handsideofthisequationbyparts,andnotingagainthatφ=0atall
pointsontheboundary,wehave
T= 2
∫∫
φdxdy (3.8)