2019-03-01_Physics_Times

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Introduction Method - Method - Method- In oscillations chapter we come across problems related to meeting of two blocks that are ...

sin sin( ) 2 A A A t A t       sin sin( ) cos 2 t t t       4 4 8 T t t         The particles can be repre ...

The two particles are shown in the figure From previous problem we already know that 3 ' 8 8 T T t   t The particles are repr ...

3 7 2 5 2 2 t       7 8 T  t For n 7 3 7 2 t t       11 11 2 2 8 T t t      So the two particles meet at 3 ...

EXPLOSION OF A PARTICLE A body falling vertically downwards under the gravity breaks in two parts of unequal masses. The centre ...

(a)   2 (^212) p m m (b) 2 (^212) p mm (c) (^2)  1 2  (^2) 1 2 p m m mm  (d)   2 (^212) p m m A shell is fired from a c ...

So momentum of two pieces after explosion ( cos ) 2 2 m m   v  V By the law of conservation of momentum cos cos 3 cos. 2 2 m ...

PHYSICS A quantity is represented by xM L Ta b c. The percentage error in measurement of M, L and T are  %, % %and respectiv ...

A cord is wound round the circumference of wheel of radius r. The axis of the wheel is horizontal and moment of inertia about it ...

(d) Component of C  along A  -component of D  along A A motor cycle engine delivers a power 10 kW, by consuming petrol at th ...

33. 34. 31. 32. observed to be red shifted by 10Å. Find the speed with which star is receding away from the earth. (a) 5 10 /^5 ...

Find out the value of current through 2  resistance for the given circuit (a) 5 A (b) 2 A (c) Zero (d) 4 A A group of N cells w ...

An alternating current of frequency ' 'f is flowing in a circuit containing a resistance R and a choke L in series. The impedanc ...

2 ext Self 2 GM W U R    A geostationary satellite goes around the earth in west-east direction. The time period a geostation ...

2 4 (300) 9 T         T 2 675 K Rise in temperature = 675 - 300= 375 K According to definition of cross-product C D  ...

cos ' cos f f v vt v v          f'f D d   (i) ' ' D d    (ii) Subtract (ii) from (i), we get   ' ' D D d   ...

75 60 2 ln 80 60 hr K           (i) The time of death is 80 60 ln d 98 60 t K           (ii) From the above ...