Barrons SAT Subject Test Chemistry, 13th Edition

(E) Since in this reaction 4 volumes of gases are forming 2 volumes of product, the randomness of the system is decreasing. The ...

(D) The reaction is Cl 2 (g) + 2Br− (aq) → 2Cl− + Br 2 (aq) Here 2 mol of chloride ions and 1 mol of Br 2 molecules are produc ...

(D) Glucose, C 6 H 12 O 6 , is a polar molecule (as are all sugars) and dissolves in water because water is also a polar molec ...

62. (A) HB H+ + B− Since [H+] is in the numerator of Ka: The stronger the acid, the greater are [H+] and the Ka value. Of the ch ...

63. (C) ...

(B) Ksp = [Ba2 +][SO 4 2−] If [Ba2+] = 4.0 × 10−5, then [SO 4 2−] must also equal the same amount, so Ksp = [4.0 × 10−5][4.0 × ...

(B) ΔH^0 reaction = ΔH^0 f (products) − ΔH^0 f (reactants) ΔH^0 reaction = −410. J − (−358. J) ΔH^0 reaction = −52. J ...

(C) Because the HCl solution will add to the chloride ion concentration, according to Le Châtelier’s Principle the equilibrium ...

(D) The oxidation state of Mn in MnO 4 − is +7 as the oxidation state of oxygen is generally −2. The oxidation state of Mn in ...

(C) A decrease in volume will cause the equilibrium to shift in the direction that has less volume(s) of gas(es). In every case ...

(E) The central P has 5 valence electrons. Of these, 2 are paired. The remaining 3 valence electrons each covalently bond with ...

(C) Change the water height to the equivalent Hg height: = 3.00 mm Hg Adjust for the difference in height to get the gas press ...

(B) The oxidation state of an element is zero. The oxidation state of a monatomic ion in a compound is the charge of the ion in ...

1. Introduction to Chemistry 1. 0.0012 g ...

63 mm ...

512 cm ...

4. 305 K 32°C + 273 = 305 K ...

5. 0.006111 L ...

1,000,000 or 1 × 10^6 mm ...

1.03 × 10^3 kg ...