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Follow the information given below : (i) A square stone with the side of 4 cm. has 16 cm. perimeter. (ii) The area of circular ...
The area of the curved surface of a right circular cylinder is 4400 sq. cn. If its height is 30 cm., find the area of its whole ...
Chapter Seventeen Statistics Owing to the contribution of information an d data, the world has become a global village for the r ...
Solution : Here the minimum and maximum numerical values of the data of temperature are 6 and 14 respectively. Hence the range = ...
Solution : Range of the data = (highest numerical value – lowest numerical value) + 1 = 90 35 + 1 = 55 + 1 = 56 Let the class ...
0DWK,;;)RUPD Diagram of Data : We have seen that the collected data under investigation are the raw materials of the stat ...
(b) The mid-points of the opposite sides parallel to the base of rectangle of the histogram have been fixed for drawing frequenc ...
Class interval 31 40 4150 5160 6170 7180 8190 91 100 Mid-point 355 2 40 31 ^45 5 555 655 755 854 95^5 Frequency ...
Activity : Make cumulative frequency table of the marks obtained 50 and above in Mathematics by the students of your class in an ...
Arithmetic mean of classified data (short-cut method) The short-cut method is easy for determining arithmetic mean of classified ...
= 4 188 20 ^37 u = 20 79 = 19 22 ? Mean production cost is Tk. 1922 hundred. Weighted mean : In many cases the numerical ...
Activity : Collect the rate of passing students and their numbers in S.S.C. examination of some schools in your Upazilla and fin ...
= 2 Thesumof valuesof30th and31th terms = 75 2 150 2 70 80 ? Required Median is 75. Activity : 1. Make frequency distribution ...
0DWK,;;)RUPD = 48 + (35 31) u 25 (^6) = 48 + 4 u 25 6 = 48 + 0 96 = 48 96 Required median is 48 96 Activity : Make ...
? Mode = 61 + 10 7 4 10 61 4 3 4 u u = 61 + 61 57 667 7 40 Therefore, the required mode is 66 714 Example 14. Find th ...
h 10 Therefore, mode = 41 + 10 25 5 u = 41 + 2 = 43 The required mode is 43. Exercise 17 Put tick (√) mark in the correct answer ...
Class Interval 31 40 4150 5160 6180 7180 8190 91 100 Frequency 6 12 16 24 12 8 2 Cumulative Frequency 6 18 34 58 70 78 80 ...
The frequency distribution table of weights (in kg) of 60 students of a class are: Interval 45-49 50-54 55-59 60-64 65-69 70-7 ...
Answer Exercise 1 (a) 0 1 6 (b) 0 6 3 (c) 3 2 (d) 3 53 5. (a) 9 2 (b) 99 35 (c) 15 2 (d) 90 71 3 (e) 3330 769 ...
Exercise 2⋅ 2 4.{( 3 , 2 ),( 4 , 2 )} 5. {( 2 , 4 ),( 2 , 6 )} 6. 16 7 7 , 23 , 7. 2 8. 1 or 2 or 3 9. x 4 (a) { 2 },{ 1 , ...
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