Structural Engineering

Draft 4.3Reactions 81 P=2560k L/2 Q=22,280k TOTAL LOADS











 


 


 
 
 
 
 
 
 
 
 
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Draft 4.4InternalForces 83 INCLINED INTERNAL FORCE: N KNOWN VERTICAL COMPONENT: H COMPONENT: V HORIZONTAL CONSEQUENT b=18.4^0 V ...

Draft Chapter 5 REVIEW of STATICS To every action there is an equal and opposite reaction. Newton'sthirdlaw of motion 5.1 Reacti ...

Draft 5.1Reactions 87 StructureType Equations Beam,noaxialforces Fy Mz 2DTruss,Frame,Beam Fx Fy Mz Grid Fz Mx My 3DTruss ...

Draft 5.1Reactions 89 Figure5.4:GeometricInstability Causedby Concurrent Reactions 5.1.5 Examples 29 Examplesof reaction calcula ...

Draft 5.1Reactions 91 Isolatingbd: (+ 
) Md= 0; (17:7)(18)(40)(15)(4)(8)(8)(30)(2)+Rcy(12)= 0 )Rcy= 1 ; 236 12 = 103 k 6 (+ ...

Draft 5.2Trusses 93 5.2 Trusses 5.2.1 Assumptions 30 Cablesandtrussesare2Dor 3Dstructurescomposedof anassemblageof simpleonedime ...

Draft 5.2Trusses 95 Figure5.6:A StaticallyIndeterminateTruss Sketch a freebodydiagramshowingalljoint loads(includingreactions) ...

Draft 5.2Trusses 97 NodeA:ClearlyAHis undercompression,andABundertension. (+ 6 ) Fy= 0; ) FAH y 58 = 0 FAH= l ly (FAH y ) ly= 3 ...

Draft 5.3Shear& Moment Diagrams 99 + +ve Shear +ve Load + Axial Force +ve Moment Figure5.9:ShearandMoment SignConvention ...

Draft 5.3Shear& Moment Diagrams 101 Thechangein moment between 1 and 2 ,
M 21 , is equalto theareaunder theshearcurve betwee ...

Draft 5.3Shear& Moment Diagrams 103 Reactions aredeterminedfromtheequilibriumequations (+  ) Fx= 0; ) RA x + 6 = 0)RA x = ...

Draft 5.3Shear& Moment Diagrams 105 ...

Draft 5.3Shear& Moment Diagrams 107 If we needto determinethemaximummoment alongBC, we know that dMBC dx = 0 at thepoint w ...

Draft 5.3Shear& Moment Diagrams 109 BaseatBtheshearforcewas determinedearlierandwas equalto 2: 246 k. Based ontheorientati ...

Draft 5.3Shear& Moment Diagrams 111 Example5-9: ShearMoment DiagramsforInclinedFrame x y F/Fy=z/x F/Fx=z/y Fx/Fy=y/x Fy Fx F ...

Draft 5.4Flexure 113 whereyis measuredfromtheaxisof rotation(neutralaxis). Thus strainsareproportionalto thedistancefromtheneutr ...

Draft 5.4Flexure 115 b y x h Y X A = bh x = b 2 y = h 2 Ix = bh 3 12 Iy = hb 3 (^12) b’ b h h’ x y X Y A = bhb 0 h 0 x = b 2 y = ...

Draft 5.4Flexure 117 We now setthosetwo valuesequalto theirrespective maximum
max = L 360 = (20)ft(12)in/ft 360 = 0: 67 in= 6 ...

Draft 5.4Flexure 119 Figure5.16:ApproximateAnalysisof Beams ...