Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

Complex numbers 221


=( 1. 732 +j 1. 000 )+( 3. 536 −j 3. 536 )
−(− 2. 000 +j 3. 464 )
= 7. 268 −j 6. 000 ,which lies in the fourth quadrant

=


[( 7. 268 )^2 +( 6. 000 )^2 ]∠tan−^1

(
− 6. 000
7. 268

)

= 9. 425 ∠− 39. 54 ◦

Now try the following exercise


Exercise 88 Further problemson polar
form


  1. Determine the modulus and argument of
    (a) 2+j4(b)− 5 −j2(c)j( 2 −j).




(a) 4. 472 , 63. 43 ◦
(b)5. 385 ,− 158. 20 ◦
(c) 2. 236 , 63. 43 ◦




In Problems 2 and 3 express the given Cartesian
complex numbers in polar form, leaving answers
in surd form.


  1. (a) 2+j3(b)−4(c)− 6 +j
    [
    (a)



13 ∠ 56. 31 ◦ (b)4∠ 180 ◦
(c)


37 ∠ 170. 54 ◦

]


  1. (a)−j3(b)(− 2 +j)^3 (c)j^3 ( 1 −j)
    [
    (a)3∠− 90 ◦ (b)



125 ∠ 100. 30 ◦
(c)


2 ∠− 135 ◦

]

In Problems 4 and 5 convert the given polar com-
plex numbers into(a+jb)form giving answers
correct to 4 significant figures.


  1. (a) 5∠ 30 ◦(b) 3∠ 60 ◦(c) 7∠ 45 ◦




(a) 4. 330 +j 2. 500
(b)1. 500 +j 2. 598
(c) 4. 950 +j 4. 950





  1. (a) 6∠ 125 ◦(b) 4∠π(c) 3. 5 ∠− 120 ◦




(a)− 3. 441 +j 4. 915
(b)− 4. 000 +j 0
(c)− 1. 750 −j 3. 031




In Problems 6 to 8, evaluate in polar form.


  1. (a) 3∠ 20 ◦× 15 ∠ 45 ◦
    (b) 2. 4 ∠ 65 ◦× 4. 4 ∠− 21 ◦
    [(a) 45∠ 65 ◦(b) 10. 56 ∠ 44 ◦]

  2. (a) 6. 4 ∠ 27 ◦÷ 2 ∠− 15 ◦
    (b) 5∠ 30 ◦× 4 ∠ 80 ◦÷ 10 ∠− 40 ◦
    [(a) 3. 2 ∠ 42 ◦(b) 2∠ 150 ◦]

  3. (a) 4∠


π
6

+ 3 ∠

π
8
(b) 2∠ 120 ◦+ 5. 2 ∠ 58 ◦− 1. 6 ∠− 40 ◦
[(a) 6. 986 ∠ 26. 79 ◦(b) 7. 190 ∠ 85. 77 ◦]

20.8 Applications of complex numbers

There are several applications of complex numbers
in science and engineering, in particular in electrical
alternating current theory and in mechanical vector
analysis.
The effect of multiplying a phasor by jis to rotate
it in a positive direction (i.e. anticlockwise) on an
Argand diagram through90◦without altering its length.
Similarly, multiplying a phasor by−jrotates the pha-
sor through− 90 ◦. These facts are used in a.c. the-
ory since certain quantities in the phasor diagrams
lie at 90◦to each other. For example, in the R−L
series circuit shown in Fig. 20.8(a),VL leads I by
90 ◦(i.e. I lagsVLby 90◦) and may be written as
jVL, the vertical axis being regarded as the imagi-
nary axis of an Argand diagram. ThusVR+jVL=V
and sinceVR=IR,V=IXL(whereXLis the induc-
tive reactance, 2πfLohms) andV=IZ(whereZis
the impedance) thenR+jXL=Z.

Phasor diagram Phasor diagram

VR VL

R

V

I

L

(a)

VR

V

I

VL



VR VC

R

V

I

C

(b)

VR

VC
V

I


Figure 20.8
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