Scalar and vector products 279
The direction cosines are:
cosα=x
√
x^2 +y^2 +z^2=3
√
14=0.802cosβ=y
√
x^2 +y^2 +z^2=2
√
14=0.535and cosγ=
y
√
x^2 +y^2 +z^2=1
√
14=0.267(and henceα=cos−^10. 802 = 36. 7 ◦,β=cos−^10. 535 =
57.7◦andγ=cos−^10. 267 = 74. 5 ◦).
Notethatcos^2 α+cos^2 β+cos^2 γ= 0. 8022 + 0. 5352 +
0. 2672 =1.
Practical application of scalar product
Problem 6. A constant force of
F= 10 i+ 2 j−knewtons displaces an object from
A=i+j+ktoB= 2 i−j+ 3 k(in metres). Find the
work done in newton metres.One of the applications of scalar products is to the work
done by a constant force when movinga body. The work
done is the product of the applied force and the distance
moved in the direction of the force.
i.e. work done=F•dThe principles developed in Problem 13, page 262,
apply equally to this problem when determining the
displacement. From the sketch shown in Fig. 26.8,
AB=AO+OB=OB−OAthat is AB=( 2 i−j+ 3 k)−(i+j+k)
=i− 2 j+ 2 kA (1,1,1)B (2, 2 1, 3)O (0, 0, 0)Figure 26.8
The work done isF•d,thatisF•ABin this case
i.e.work done=( 10 i+ 2 j−k)•(i− 2 j+ 2 k)
But from equation (2),a•b=a 1 b 1 +a 2 b 2 +a 3 b 3Hencework done=
( 10 × 1 )+( 2 ×(− 2 ))+((− 1 )× 2 )=4Nm.
(Theoretically, it is quite possible to get a negative
answer to a ‘work done’ problem. This indicates that
the force must be in the opposite sense to that given, in
order to give the displacement stated.)Now try the following exerciseExercise 112 Further problemson scalar
products- Find the scalar producta•bwhen
(i) a=i+ 2 j−kandb= 2 i+ 3 j+k
(ii) a=i− 3 j+kandb= 2 i+j+k
[(i) 7 (ii) 0]
Givenp= 2 i− 3 j,q= 4 j−kand
r=i+ 2 j− 3 k, determine the quantities
stated in problems 2 to 8. - (a)p•q (b)p•r [(a)−12 (b)−4]
- (a)q•r (b)r•q [(a) 11 (b) 11]
- (a)|p| (b)|r| [(a)
√
13 (b)√
14]- (a)p•(q+r) (b) 2r•(q− 2 p)
[(a)−16 (b) 38] - (a)|p+r| (b)|p|+|r|
[(a)
√
19 (b) 7.347]- Find the angle between (a) p and q
(b)qandr. [(a) 143.82◦(b) 44.52◦] - Determine the direction cosines of (a) p
(b)q(c)r.
⎡
⎣
(a) 0. 555 ,− 0. 832 , 0
(b) 0 , 0. 970 ,− 0. 243
(c) 0. 267 , 0. 535 ,− 0. 802⎤
⎦- Determine the angle between the forces:
F 1 = 3 i+ 4 j+ 5 kandF 2 =i+j+k [11. 54 ◦]