5 Steps to a 5 AP Chemistry
formed, an HA must have dissociated. However, many times if Ka is small, you can approximate the equilibrium concentration of th ...
For polyprotic acids, acids that can donate more than one proton, the Kafor the first dissociation is much larger than the Kafor ...
The pOH of a solution can also be calculated. It is defined as pOH =−log[OH−]. The pH and the pOH are related: In any of the pro ...
The equilibrium constant expression is called the weak base dissociation constant, Kb, and has the form: The same reasoning that ...
The resultant solution, since strontium acetate is soluble, has 0.200 M Sr^2 +and 0.400 M C 2 H 3 O 2 −. Ions such as Sr^2 +, wh ...
the two ions. The larger Kvalue predominates. If the larger value is Ka, the solution is acidic. If the larger value is Kb, the ...
Assume xsmall Alternate solution: Titration Equilibria An acid–base titrationis a laboratory procedure commonly used to determin ...
Let’s consider a typical titration problem. A 100.0 mL sample of 0.150 M nitrous acid (pKa= 3.35) was titrated with 0.300 M sodi ...
Based on the stoichiometry of the problem, and on the moles of acid and base, NaOH is the limiting reagent. The stoichiometry pa ...
Since a CA/CB pair is present, this is now a buffer problem, and the Henderson– Hasselbalch equation may be used. pH =pKa+log (C ...
The strong base will control the pH. [OH−] =0.0015 mol/0.155 L =9.7 × 10 −^3 M The stoichiometry part of the problem is finished ...
solids, liquids, and solvents are included in the equilibrium constant.) The Kspexpression for the PbSO 4 system would be: For t ...
b. 1.00 M Na 2 CrO 4 →1.00 M CrO 42 −(common ion) Ksp=(2x)^2 (1.00 + x) =1.9 × 10 −^12 = 4 x^2 (neglect x) x=6.9 × 10 −^6 M [Ag+ ...
amount of at least one of the substances is determined. Based on the change in this one sub- stance and the stoichiometry, the a ...
232 Step 4. Review the Knowledge You Need to Score High Ionization Constants: HCOOH Ka = 1.8 × 10 −^4 CH 3 NH 2 Kb=4.4 × 10 −^ ...
Equilibrium 233 17.A student wishes to reduce the zinc ion concentra- tion in a saturated zinc iodate solution to 1 × 10 −^6 M ...
234 Step 4. Review the Knowledge You Need to Score High 25.C 2 H 4 (g) +3 O 2 (g) 2 CO 2 (g) +2 H 2 O(g) An equal number of mo ...
Answers and Explanations Equilibrium 235 B—An acid, any acid, will give a pH below 7; thus, answers C–E are eliminated. A 0 ...
A—When dealing with gaseous equilibria, volume changes are important when there is a difference in the total number of moles of ...
29.B—The low value of Kmeans that the equilib- rium lies to the left. The equilibrium always lies away from the stronger acid an ...
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