166 4. Particular Determinants
β 2 i, 2 i=λii,i≥ 1 ,
β 2 i+1, 2 j+1=λij, 0 ≤j≤i,
β 2 i+2, 2 j=λi+1,j−λij, 1 ≤j≤i+1, (4.13.6)
λij=
i
i+j
(
i+j
2 j
)
;
λii=
1
2
,i>0; λi 0 =1,i≥ 0. (4.13.7)
The functionsλijandfr(x) appear in Appendix A.10.
Theorem 4.60.
M=NKN
T
.
Proof. Let
G=[γij]n=NKN
T
. (4.13.8)
Then
G
T
=NK
T
N
T
=NKN
T
=G.
Hence,Gis symmetric, and sinceMis also symmetric, it is sufficient to
prove thatαij=γijforj≤i. There are four cases to consider:
i.i, jboth odd,
ii.iodd,jeven,
iii.ieven,jodd,
iv.i, jboth even.
To prove case (i), puti=2p+1 andj=2q+1 and refer to Appendix A.10,
where the definition ofgr(x) is given in (A.10.7), the relationships between
fr(x) andgr(x) are given in Lemmas (a) and (b) and identities among the
gr(x) are given in Theorem 4.61.
α 2 p+1, 2 q+1=u 2 q+2p+u 2 q− 2 p
=
N
∑
j=1
aj
{
f 2 q+2p(xj)+f 2 q− 2 p(xj)
}
=
N
∑
j=1
aj
{
gq+p(xj)+gq−p(xj)
}
=2
N
∑
j=1
ajgp(xj)gq(xj). (4.13.9)
It follows from (4.13.8) and the formula for the product of three matrices
(the exercise at the end of Section 3.3.5) with appropriate adjustments to