9.7Tension Field Beams 317Fig.9.17
Determination of plastic hinge position.
Then,Sxccφ= 2 Mpc′φ+σtctwsin^2 θc^2 c
2φTheminimumvalueofSxisobtainedbydifferentiatingwithrespecttocc,thatis,dSx
dcc=− 2
Mpc′
c^2 c+σtctwsin^2 θ
2= 0
whichgives
c^2 c=4 Mpc′
σtctwsin^2 θ(9.56)
Similarly,inthetensionflange,
c^2 t=4 Mpt′
σtttwsin^2 θ(9.57)
Clearly,fortheplastichingestooccurwithinaflange,bothccandctmustbelessthanb.Therefore,
fromEq.(9.56),
Mpc′ <twb^2 sin^2 θ
4σtc (9.58)whereσtcisfoundfromEqs.(9.52)and(9.53)atthemidpointofWX.
TheaverageaxialstressinthecompressionflangebetweenWandXisobtainedbyconsideringthe
equilibriumofhalfofthelengthofWX(Fig.9.18).
Then,
Fc=σcfAcf+σtctwcc
2sinθcosθ+τmtwcc
2