Engineering Mechanics

(^528) „„„„„ A Textbook of Engineering Mechanics 528528 Helical Springs and Pendulums 26 CHAPTERCHAPTERCHAPTERCHAPTERCHAPTER Con ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 529 Let a body be attached to the lower end. Let A-A be the equilibrium positio ...

(^530) „„„„„ A Textbook of Engineering Mechanics We know that periodic time, 11 0.5 s 2 t n We also know that periodic time, 4 0 ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 531 Maximum force in the spring We know that the angular velocity of the body, ...

(^532) „„„„„ A Textbook of Engineering Mechanics EXERCISE 26.1 A helical spring has a stiffness of 1 N/mm. What mass should be ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 533 Notes. 1. We have considered only two springs for the sake of simplicity. B ...

(^534) „„„„„ A Textbook of Engineering Mechanics (b) When the springs are connected in parallel We know that spring constant of ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 535 Let P 1 = Weight shared by the upper spring, and P 2 = Weight shared by the ...

(^536) „„„„„ A Textbook of Engineering Mechanics Consider the equilibrium of the system at C. The weight mg of the bob can be re ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 537 Law of mass. It states, “The time period (t) of a simple pendulum does not ...

(^538) „„„„„ A Textbook of Engineering Mechanics Fig. 26.6. (d) Maximum angular velocity of the bob We also know that maximum an ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 539 t = Time period for one oscillation and n = No. of beats or swings in time ...

(^540) „„„„„ A Textbook of Engineering Mechanics We also know that 2 dn dg ng –1 86 400 2 301 dn × ∴ 86 400 ––143·5s 2301 dn== × ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 541 Let l = Length of the string, t = Time period, n = No. of beats in time t, ...

(^542) „„„„„ A Textbook of Engineering Mechanics Fig. 26.7. Compound pendulum –20 86 400 6400 h = ∴ 20 6400 1·48 km 86 400 h × ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 543 Now let I 0 = Mass moment of inertia of the body about O α = Angular accele ...

(^544) „„„„„ A Textbook of Engineering Mechanics Example 26.14. A block whose weight = W is suspended by means of a spring whose ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 545 ∴Total deflection of cantilever at A, 22 1212 Wl W 11 l W kb k kb k ⎛⎞ ⎡⎤⎛⎞ ...

(^546) „„„„„ A Textbook of Engineering Mechanics Fig. 26.12. Centre of oscillation. We know that extension of the spring, δ = 0· ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 547 Now the force (P) acting at G will produce an acceleration (a) such that, P ...