Engineering Mechanics
(^708) A Textbook of Engineering Mechanics Now assume* T 4 = 8 and T 3 = 4 T 4 = 4 × 8 = 32 Substituting the values of T 3 ...
Chapter 34 : Transmission of Power by Gear Trains 709 First of all, consider the arm C to be fixed. Therefore axes of both ...
(^710) A Textbook of Engineering Mechanics We know that the speed of the wheel A, relative to the arm C =NA – NC and speed ...
Chapter 34 : Transmission of Power by Gear Trains 711 Speed of wheel B when wheel A is fixed Since the speed of arm is 150 ...
(^712) A Textbook of Engineering Mechanics Speed of wheel B when wheel A makes 300 r.p.m. Since the wheel A makes 300 r.p. ...
Chapter 34 : Transmission of Power by Gear Trains 713 First of all, prepare the table of motions as given below : Step No. ...
(^714) A Textbook of Engineering Mechanics Example 34.8. An epicyclic gear train as shown in Fig. 34.15, has a sun wheel S ...
Chapter 34 : Transmission of Power by Gear Trains 715 Since the no. of teeth are proportional to their diameters, therefor ...
(^716) A Textbook of Engineering Mechanics First of all, prepare the table of motions as below. Step No. Condition of moti ...
Chapter 34 : Transmission of Power by Gear Trains 717 QUESTIONS Explain the advantages of gear drive over the belt and ro ...
(^718) A Textbook of Engineering Mechanics 718 Hydrostatics 35.1.INTRODUCTION The term ‘hydrostatics’ means the study of p ...
Chapter 35 : Hydrostatics 719 Mathematically, if P is the total pressure (or force) acting on area a, then the intensity o ...
(^720) A Textbook of Engineering Mechanics 35.4.PRESSURE HEAD We have already discussed in the last article, that when a l ...
Chapter 35 : Hydrostatics 721 35.6.TOTAL PRESSURE ON AN IMMERSED SURFACE As a matter of fact, an immersed surface may be p ...
(^722) A Textbook of Engineering Mechanics Divide the whole surface into a no. of small parallel strips as shown in the fi ...
Chapter 35 : Hydrostatics 723 Example 35.5. A circular door of 1 m diameter closes on an opening in the vertical side of a ...
(^724) A Textbook of Engineering Mechanics Now from the geometry of the figure, we find that AD : AC =x 1 : x 2 = 612 ABD ...
Chapter 35 : Hydrostatics 725 But ∫ lb dx = Moment of the surface area about O = sin Ax θ ∴ P = sin sin Ax w θ× θ =wax ... ...
(^726) A Textbook of Engineering Mechanics gravity of the immersed surface and towards the lower edge of the figure. The p ...
Chapter 35 : Hydrostatics 727 M=wxbdx∫^2 But ∫xbdx^2 =I 0 ∴ M=wI 0 ...(i) where I 0 = Moment of inertia of the pressure ab ...
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