Engineering Mechanics

(^648) „„„„„ A Textbook of Engineering Mechanics ∴ F= 2 22 Ia Mk a rr = ... (Q I = mk^2 ) ...(ii) and now substituting the value ...

Chapter 31 : Kinetics of Motion of Rotation „„„„„ 649 Example 31.17. A solid uniformly thick wheel of radius 1 m and mass 40 kg ...

(^650) „„„„„ A Textbook of Engineering Mechanics QUESTIONS What is torque? Give an example of torque. State the Newton’s Laws o ...

Chapter 32 : Motion of Vehicles „„„„„ 651 32 CHAPTERCHAPTERCHAPTERCHAPTERCHAPTER Contents Introduction. Types of Motions of Veh ...

(^652) „„„„„ A Textbook of Engineering Mechanics 32.2.TYPES OF MOTIONS OF VEHICLES Though there are many types of vehicles and t ...

Chapter 32 : Motion of Vehicles „„„„„ 653 A little consideration will show that the horizontal forces acting on the vehicle may ...

(^654) „„„„„ A Textbook of Engineering Mechanics Now taking moments about the centre of gravity (G) of the vehicle, RF x – RR x= ...

Chapter 32 : Motion of Vehicles „„„„„ 655 and reaction on the rear pair of wheels, RR= 2 1 2 h IP Mg x IMr ⎡⎤⎛⎞ ⎢⎥⎜⎟+ ⎣⎦⎝⎠ = 2 ...

(^656) „„„„„ A Textbook of Engineering Mechanics A force equal to 2F passing through the c.g. of the vehicle (but acting opposi ...

Chapter 32 : Motion of Vehicles „„„„„ 657 = 2 2 hI P Py xxr I M r × ⎛⎞ ⎜⎟+ ⎝⎠^2 P a I M r ⎡⎤ ⎢⎥= ⎢⎥⎛⎞ ⎜⎟+ ⎢⎥⎣⎦⎝⎠ Q = 2 – P hI ...

(^658) „„„„„ A Textbook of Engineering Mechanics Find from first principles, the (i) acceleration of the vehicle and (ii) normal ...

Chapter 32 : Motion of Vehicles „„„„„ 659 32.5.DRIVING OF A VEHICLE We have already discussed in Arts. 32.3 and 32.4 the motion ...

(^660) „„„„„ A Textbook of Engineering Mechanics We know that RF + RR=Mg = 800 × 9·8 = 7840 N ...(i) Since the car is moving wit ...

Chapter 32 : Motion of Vehicles „„„„„ 661 1·15 RF – 0·51 RF= 1·6 RR ∴ RR= 0·64 0·4 1·6 F F R = R Substituting this value of RR i ...

(^662) „„„„„ A Textbook of Engineering Mechanics Example 32.5. An automobile of mass 4000 kg is travelling at 45 km.p.h. on a le ...

Chapter 32 : Motion of Vehicles „„„„„ 663 This resisting force stops the automobile in a distance of s 1 metres. Therefore work ...

(^664) „„„„„ A Textbook of Engineering Mechanics (iii) Distance covered by the automobile in coming to stop, if the brakes are a ...

Chapter 32 : Motion of Vehicles „„„„„ 665 Example 32.6. A vehicle of mass 2250 kg having its wheel base of 1·8 m is travelling a ...

(^666) „„„„„ A Textbook of Engineering Mechanics Now let a 1 = Retardation of the vehicle, and t 1 = Time taken by the vehicle i ...

Chapter 32 : Motion of Vehicles „„„„„ 667 ∴ a 2 = 100 –3.125m/s 2 (2 16) = × ...(Minus sin due to retardation) and final veloc ...