316 DIFFERENTIAL CALCULUS
(a)x=4(θ−sinθ),
hence
dx
dθ
= 4 −4 cosθ=4(1−cosθ)
y=4(1−cosθ), hence
dy
dθ
=4 sinθ
From equation (1),
dy
dx
=
dy
dθ
dx
dθ
=
4 sinθ
4(1−cosθ)
=
sinθ
( 1 −cosθ)
(b) From equation (2),
d^2 y
dx^2
=
d
dθ
(
dy
dx
)
dx
dθ
=
d
dθ
(
sinθ
1 −cosθ
)
4(1−cosθ)
=
(1−cosθ)(cosθ)−(sinθ)(sinθ)
( 1 −cosθ)^2
4(1−cosθ)
=
cosθ−cos^2 θ−sin^2 θ
4(1−cosθ)^3
=
cosθ−
(
cos^2 θ+sin^2 θ
)
4(1−cosθ)^3
=
cosθ− 1
4(1−cosθ)^3
=
−(1−cosθ)
4(1−cosθ)^3
=
− 1
4 ( 1 −cosθ)^2
Now try the following exercise.
Exercise 128 Further problems on differen-
tiation of parametric equations
- Givenx= 3 t−1 andy=t(t−1), determine
dy
dx
in terms oft.
[
1
3
(2t−1)
]
- A parabola has parametric equations:
x=t^2 , y= 2 t. Evaluate
dy
dx
whent= 0. 5
[2]
- The parametric equations for an ellipse
arex=4 cosθ,y=sinθ. Determine (a)
dy
dx
(b)
d^2 y
dx^2
[
(a)−
1
4
cotθ (b)−
1
16
cosec^3 θ
]
- Evaluate
dy
dx
at θ=
π
6
radians for the
hyperbola whose parametric equations are
x=3 secθ,y=6 tanθ. [4]
- The parametric equations for a rectangular
hyperbola are x= 2 t,y=
2
t
. Evaluate
dy
dx
whent= 0. 40 [−6.25]
The equation of a tangent drawn to a curve at
point (x 1 ,y 1 ) is given by:
y−y 1 =
dy 1
dx 1
(x−x 1 )
Use this in Problems 6 and 7.
- Determine the equation of the tangent drawn
to the ellipsex=3 cosθ,y=2 sinθatθ=
π
6
.
[y=− 1. 155 x+4]
- Determine the equation of the tangent drawn
to the rectangular hyperbolax= 5 t,y=
5
t
at
t=2. [
y=−
1
4
x+ 5
]
29.4 Further worked problems on
differentiation of parametric
equations
Problem 5. The equation of the normal drawn
to a curve at point(x 1 ,y 1 )is given by:
y−y 1 =−
1
dy 1
dx 1
(x−x 1 )
Determine the equation of the normal drawn to
the astroidx=2 cos^3 θ, y=2 sin^3 θat the point
θ=
π
4
x=2 cos^3 θ, hence
dx
dθ
=−6 cos^2 θsinθ
y=2 sin^3 θ, hence
dy
dθ
=6 sin^2 θcosθ