Higher Engineering Mathematics

(Greg DeLong) #1
316 DIFFERENTIAL CALCULUS

(a)x=4(θ−sinθ),


hence

dx

= 4 −4 cosθ=4(1−cosθ)

y=4(1−cosθ), hence

dy

=4 sinθ

From equation (1),

dy
dx

=

dy

dx

=

4 sinθ
4(1−cosθ)

=

sinθ
( 1 −cosθ)

(b) From equation (2),


d^2 y
dx^2

=

d

(
dy
dx

)

dx

=

d

(
sinθ
1 −cosθ

)

4(1−cosθ)

=

(1−cosθ)(cosθ)−(sinθ)(sinθ)
( 1 −cosθ)^2
4(1−cosθ)

=

cosθ−cos^2 θ−sin^2 θ
4(1−cosθ)^3

=

cosθ−

(
cos^2 θ+sin^2 θ

)

4(1−cosθ)^3

=

cosθ− 1
4(1−cosθ)^3

=

−(1−cosθ)
4(1−cosθ)^3

=

− 1
4 ( 1 −cosθ)^2

Now try the following exercise.

Exercise 128 Further problems on differen-
tiation of parametric equations


  1. Givenx= 3 t−1 andy=t(t−1), determine
    dy
    dx


in terms oft.

[
1
3

(2t−1)

]


  1. A parabola has parametric equations:


x=t^2 , y= 2 t. Evaluate

dy
dx

whent= 0. 5
[2]


  1. The parametric equations for an ellipse


arex=4 cosθ,y=sinθ. Determine (a)

dy
dx

(b)

d^2 y
dx^2

[
(a)−

1
4

cotθ (b)−

1
16

cosec^3 θ

]


  1. Evaluate


dy
dx

at θ=

π
6

radians for the
hyperbola whose parametric equations are
x=3 secθ,y=6 tanθ. [4]


  1. The parametric equations for a rectangular


hyperbola are x= 2 t,y=

2
t

. Evaluate


dy
dx
whent= 0. 40 [−6.25]

The equation of a tangent drawn to a curve at
point (x 1 ,y 1 ) is given by:

y−y 1 =

dy 1
dx 1

(x−x 1 )

Use this in Problems 6 and 7.


  1. Determine the equation of the tangent drawn
    to the ellipsex=3 cosθ,y=2 sinθatθ=


π
6

.
[y=− 1. 155 x+4]


  1. Determine the equation of the tangent drawn


to the rectangular hyperbolax= 5 t,y=

5
t

at
t=2. [

y=−

1
4

x+ 5

]

29.4 Further worked problems on
differentiation of parametric
equations

Problem 5. The equation of the normal drawn
to a curve at point(x 1 ,y 1 )is given by:

y−y 1 =−

1
dy 1
dx 1

(x−x 1 )

Determine the equation of the normal drawn to
the astroidx=2 cos^3 θ, y=2 sin^3 θat the point
θ=

π
4

x=2 cos^3 θ, hence

dx

=−6 cos^2 θsinθ

y=2 sin^3 θ, hence

dy

=6 sin^2 θcosθ
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