Appendix D
Solutions to Selected Problems
Chapter 6
I6-1. (a)A~+B~= 9ˆe 1 +eˆ 2 + 3ˆe 3 (b) 6A~− 3 B~= 15ˆe 2 (c)A~+ 2B~= 15ˆe 1 + 5ˆe 3
I6-2.
A~+B~=C~
A~+D~ =B~
Since the vectors are coplaner there exists scalar constantsα andβ such that
A~+αD~=βC~ This implies
A~+α(B~−A~) =β(A~+B~) or A~(1−α−β) +B~(α−β) =~ 0
SinceA~andB~ are linearly independent and noncolinear one can state that
1 =α+β and 0 =α−β
Solving these simultaneous equations givesα= 1/ 2 andβ= 1/ 2 which demonstrates
that the diagonals bisect one another.
I6-3.
LetA~+B~=C~and then by construction write
1
2
A~+D~+^1
2
B~=C~=A~+B~
so that
D~=^1
2
A~+^1
2
B~=^1
2
C~
Solutions Chapter 6