Everything Science Grade 11

CHAPTER 16. THE PHYSICS OF MUSIC 16.5 fundamental frequency higher frequencies higher frequencies resultant waveform Figure 16.4 ...

16.5 CHAPTER 16. THE PHYSICS OF MUSIC The wavelength of astanding wave in a pipewith one end open canbe calculated using λn= 2 ...

CHAPTER 16. THE PHYSICS OF MUSIC 16.5 Chapter 16 End of Chapter Exercises A guitar string with alength of 70 cm is plucked. The ...

Electrostatics 17 17.1 Introduction ESBHD In Grade 10, you learntabout the force betweencharges. In this chapteryou will learn e ...

CHAPTER 17. ELECTROSTATICS 17.2 where m 1 and m 2 are the masses of the two particles, r is the distance betweenthem, and G is t ...

17.2 CHAPTER 17. ELECTROSTATICS Thus the magnitude of the force is 3 , 37 × 10 −^8 N. However since both point charges have oppo ...

CHAPTER 17. ELECTROSTATICS 17.2 Fe = k Q 1 Q 2 r^2 = (8, 99 × 109 ) (− 1 , 60 × 10 −^19 )(− 1 , 60 × 10 −^19 ) (10−^10 )^2 = 2, ...

17.2 CHAPTER 17. ELECTROSTATICS because force is a vector quantity. Step 3 : Determine what is given We are given all the charge ...

CHAPTER 17. ELECTROSTATICS 17.2 – + 10kg 50cm 60 o X Y / / / / / / / / / / / \ \ \ \ \ SOLUTION How are we going to determine th ...

17.3 CHAPTER 17. ELECTROSTATICS magnitudes of the charges on X and Y are the same: QX= QY. The magnitude of the electrostatic fo ...

CHAPTER 17. ELECTROSTATICS 17.3 DEFINITION: Electric field A collection of electriccharges gives rise to a’field of vectors’ in ...

17.3 CHAPTER 17. ELECTROSTATICS Negative charge actingon a test charge If the charge, Q, were negative we would havethe followin ...

CHAPTER 17. ELECTROSTATICS 17.3 Combined charge distributions ESBHI We will now look at thefield of a positive chargeand a negat ...

17.3 CHAPTER 17. ELECTROSTATICS +Q -Q Two like charges : bothpositive For the case of two positive charges things looka little d ...

CHAPTER 17. ELECTROSTATICS 17.3 +Q +Q Working through a number of possible starting points for the test chargewe can show the el ...

17.3 CHAPTER 17. ELECTROSTATICS Parallel plates ESBHJ One very important example of electric fields which is used extensivelyis ...

CHAPTER 17. ELECTROSTATICS 17.3 The magnitude of the electric field at a point asthe force per unit charge. Therefore, E = F q E ...

17.3 CHAPTER 17. ELECTROSTATICS E = k Q r^2 = (8. 99 × 109 )(5× 10 −^9 ) (0,3)^2 = 4, 99 × 102 N.C−^1 Example 6: Electric field ...

CHAPTER 17. ELECTROSTATICS 17.4 Then for Q 2 : E = k Q r^2 = (8. 99 × 109 )(4× 10 −^9 ) (0,3)^2 = 2, 70 × 102 N.C−^1 We need to ...

17.4 CHAPTER 17. ELECTROSTATICS U = kQ 1 Q 2 r = (8. 99 × 109 )(7× 10 −^9 )(20× 10 −^9 ) (0,02) = 6, 29 × 10 −5J Electrical pote ...