SAT Subject Test Chemistry,10 edition
68 . Which of the following compounds can act as a Lewis base? (A) HClO 2 (B) NH 2 NH 2 (C) NH 4 + (D) BF 3 (E) N ...
Answer Key PRACTICE TEST 1 1 . B 2 . D 3 . E 4 . C 5 . A 6 . E 7 . A 8 . B 9 . C 10 . C 11 . ...
105 . T, F 106 . T, F 107 . T, T, CE 108 . F, T 109 . T, F 110 . T, T, CE 111 . T, T, CE 112 . T, T, CE 113 ...
49 . D 50 . B 51 . A 52 . C 53 . A 54 . C 55 . D 56 . B 57 . A 58 . B 59 . D 60 . C 61 . A 62 . C 63 ...
Answers and Explanations PRACTICE TEST 1 1. Part A 1 . B An Arrhenius acid produces H+ in solution. 2 . D A ...
proportional to its pressure. 8 . B Charles’s law states that the volume of a gaseous sample at constant pres ...
16 . E When an acid loses a proton it becomes its conjugate base. A conjugate acid is defined as the ...
26. Part B 101 . T, T, CE Gases deviate from the ideal gas law when atoms and molecules are forced into ...
Salts will not dissolve appreciably in organic solvents because they are nonpolar, and salts needs a polar ...
116 . F, T Catalysts increase the rate of a reaction by decreasing the activation energy. 117. Part C 25 . ...
The trick is understanding what should happen to each when it is dissolved in water. Choice D, potassium ...
hydrogen ion concentration in solution and the pOH is equal to the negative log of the hydroxide ion concentr ...
38 . C 5 g NaOH/40 g/mol = 0.125 mol NaOH and therefore 0.125 mole of OH–. You must have 0.125 m ...
and the bromine concentration. Plugging in the appropriate concentration values, you get 5002 over the product of ...
88 g C 3 H 8 /44g/mol = 2 mol; therefore, 7 mol of oxygen are needed. 7 mol O 2 × 32 g/mol = 224 ...
3 α and 2 β emissions will be ( + + + + ). This describes what is lost ...
56 . B 57 . A Twenty total electrons describes Ca. But it is an excited state calcium molecule, because the 3 ...
system—that is, the total energy contained in the system—will change. The potential energy of the system during the p ...
multiple of five, depending on the other compounds. There are six chlorines on the right, so you must place ...
quantum number, ms, must be different for these two electrons. So one will have an ms value equal to +1/2 ...
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