TITLE.PM5

338 ENGINEERING THERMODYNAMICS DHARM M-therm\Th6-2.PM5 Answers (a) 2. (a) 3. (d) 4. (a) 5. (d). Theoretical Questions Explain ...

AVAILABILITY AND IRREVERSIBILITY 339 DHARM M-therm\Th6-2.PM5 1000 kJ of heat leaves hot gases at 1400°C from a fire box of a bo ...

340 ENGINEERING THERMODYNAMICS DHARM M-therm\Th6-2.PM5 1 kg of air is compressed polytropically from 1 bar and 300 K to 7 bar a ...

7 Thermodynamic Relations 7.1. General aspects. 7.2. Fundamentals of partial differentiation. 7.3. Some general thermodynamic re ...

342 ENGINEERING THERMODYNAMICS dharm \M-therm\Th7-1.pm5 Then the differential of the dependent variable x is given by dx = ∂ ∂ ∂ ...

THERMODYNAMIC RELATIONS 343 dharm \M-therm\Th7-1.pm5 7.3. Some General Thermodynamic Relations The first law applied to a closed ...

344 ENGINEERING THERMODYNAMICS dharm \M-therm\Th7-1.pm5 Also, ∂ ∂ T v p svs F HG I KJ =−∂ ∂ F HG I KJ ...(7.18) ∂ ∂ T p v s s p ...

THERMODYNAMIC RELATIONS 345 dharm \M-therm\Th7-1.pm5 where cp = T ∂ ∂ s T p F HG I KJ ...(7.26) Also ∂ ∂ F HG I KJ s pT = – ∂ ∂ ...

346 ENGINEERING THERMODYNAMICS dharm \M-therm\Th7-1.pm5 To find ∂ ∂ h pT F HG I KJ ; let h = f(s, p) Then, dh = ∂ ∂ h s p F HG I ...

THERMODYNAMIC RELATIONS 347 dharm \M-therm\Th7-1.pm5 predicted from hypotheses about the microscopic structure of matter. This t ...

348 ENGINEERING THERMODYNAMICS dharm \M-therm\Th7-1.pm5 Fig. 7.2. Determination of compressibility from p-T data. K = –^1 v v pT ...

THERMODYNAMIC RELATIONS 349 dharm \M-therm\Th7-1.pm5 Consider the first quantity ∂ ∂ F HG I KJ u T v. During a process at consta ...

350 ENGINEERING THERMODYNAMICS dharm \M-therm\Th7-1.pm5 Now, from eqns. (7.34) and (7.37), we have cp – cv = β^2 Tv K ...(7.38) ...

THERMODYNAMIC RELATIONS 351 dharm \M-therm\Th7-1.pm5 Thus dh = cp dT + v(1 – βT) dp ...[7.31 (a)] (ii) Since u = h – pv or ∂ ∂ F ...

352 ENGINEERING THERMODYNAMICS dharm \M-therm\Th7-1.pm5 temperature and pressure measurements taken there will be values for the ...

THERMODYNAMIC RELATIONS 353 dharm \M-therm\Th7-1.pm5 or ∂ ∂ F HG I KJ v T p = R p = v T ∴μ =^1 c T v T v p FHG ×−IKJ = 0. Theref ...

354 ENGINEERING THERMODYNAMICS dharm \M-therm\Th7-1.pm5 The Clausius-Claperyon equation can be derived in different ways. The me ...

THERMODYNAMIC RELATIONS 355 dharm \M-therm\Th7-1.pm5 Knowing the vapour pressure p 1 at temperature T 1 we can find the vapour p ...

356 ENGINEERING THERMODYNAMICS dharm \M-therm\Th7-1.pm5 Since the above equation is true for any process, therefore, it will als ...

THERMODYNAMIC RELATIONS 357 dharm \M-therm\Th7-1.pm5 or β =^12 23 v R vb RT vb a v − − − − + L N M M M M O Q P P P () P . Rv v b ...