TITLE.PM5
378 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 To derive the equation of state for a perfect gas let us consider a unit ...
IDEAL AND REAL GASES 379 dharm \M-therm\Th8-1.pm5 The magnitude of this constant depends upon the particular gas and it is denot ...
380 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 Joule concluded this result from a series of experiments conducted with ...
IDEAL AND REAL GASES 381 dharm \M-therm\Th8-1.pm5 It may be seen that as Joule’s law for an ideal gas states u = f(T), then cv = ...
382 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 λ LM d d If the volume of one mole is considered then the above equation ...
IDEAL AND REAL GASES 383 dharm \M-therm\Th8-1.pm5 The mean free path is inversely proportional to the density of the gas, for if ...
384 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 Pressure, atm. 25 50 75 100 0 .005 .01 .015 .02 Perfect gas 40 Cº –20 Cº ...
IDEAL AND REAL GASES 385 dharm \M-therm\Th8-1.pm5 vc^3 = ab pc , and from these by a simple reduction, we have vb p a b T a bR c ...
386 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 e n F + HG I KJ 3 2 (3n – 1) = 8m In this “reduced” equation the three c ...
IDEAL AND REAL GASES 387 dharm \M-therm\Th8-1.pm5 b a^ p a v F + HG I (^2) KJ (v – b) =^1 2 F − HG I KJ b v , which reduces to v ...
388 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 We have p a v HFG +^2 KJI (v – b) = RT [From eqn. (8.15)] Keeping p cons ...
IDEAL AND REAL GASES 389 dharm \M-therm\Th8-1.pm5 p Cooling v Heating 3b 2 The form of curve given by equation (8.33) is shown i ...
390 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 that is, below – 245.9°C there would be a heating effect, between – 245. ...
IDEAL AND REAL GASES 391 dharm \M-therm\Th8-1.pm5 Table 8.2. Constants of the Beattie-Bridgeman Equation of State Gas A 0 aB 0 b ...
392 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 Carbon dioxide 44 0.840 0.650 0.190 1.3 0.274 Water 18 — — 0.462 — 0.230 ...
IDEAL AND REAL GASES 393 dharm \M-therm\Th8-1.pm5 p 1 V 1 = m 1 RT 1 orm pV (^1) RT 11 1 F HG I KJ p 2 V 2 = m 2 RT 2 orm pV (^2 ...
394 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-1.pm5 (i)What mass of original gas must have escaped if the dimensions of the ...
IDEAL AND REAL GASES 395 dharm \M-therm\Th8-2.pm5 (iv)Evaluate the increase in specific internal energy, the increase in specifi ...
396 ENGINEERING THERMODYNAMICS dharm \M-therm\Th8-2.pm5 But v 1 = v 2 ∴∆s = cv loge T T 2 1 F HG I KJ = 0.742 loge 293 363 F HG ...
IDEAL AND REAL GASES 397 dharm \M-therm\Th8-2.pm5 But γ = c c p v = 1.4 (given) ...(i) and cp – cv = R (= 0.287 kJ/kg K for air) ...
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