TITLE.PM5

518 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 → 2 (12 + 2 × 16) kg CO 2 + (2 × 1 + 16) kg H 2 O + (2) (2.5) 79 21 F ...

FUELS AND COMBUSTION 519 dharm \M-therm\Th11-2.pm5 For 200% theoretical air the combustion equation would be C 8 H 18 + (2) (12. ...

520 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 and b = 2 – a = 2 – 1.3 = 0.7 Thus the combustion equation becomes : C ...

FUELS AND COMBUSTION 521 dharm \M-therm\Th11-2.pm5 (ii)Air-fuel ratio A/F : The air-fuel ratio on a mole basis is 2.2 + 8.27 = 1 ...

522 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 Hence the analysis of the products is CO 2 = 0 068 0 467 . . × 100 = 14 ...

FUELS AND COMBUSTION 523 dharm \M-therm\Th11-2.pm5 The stoichiometric A/F ratio = 11.31/1. (Ans.) When 30 per cent excess air is ...

524 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 Solution. The example is solved by a tabular method ; a specimen calcul ...

FUELS AND COMBUSTION 525 dharm \M-therm\Th11-2.pm5 Example 11.22. Find the stoichiometric air-fuel ratio for the combustion of e ...

526 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 O 2 = 075 19 85 . . × 100 = 3.78%. (Ans.) N 2 = 14 1 19 85 . . × 100 = ...

FUELS AND COMBUSTION 527 dharm \M-therm\Th11-2.pm5 H 2 O = 3 13 678. × 100 = 21.93%. (Ans.) N 2 = 8 678 13 678 . . × 100 = 63.45 ...

528 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 If the air-fuel ratio is 7/1 by volume, calculate the analysis of the d ...

FUELS AND COMBUSTION 529 dharm \M-therm\Th11-2.pm5 i.e., x = p + q 2 + r – 0 3125 2 . = 5 + 10 2 + 0.1562 – 0 3125 2 . = 9.99 Ni ...

530 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 Hence the combustion equation becomes C 7 H 10 O0.218N0.107 + 9.39O 2 + ...

FUELS AND COMBUSTION 531 dharm \M-therm\Th11-2.pm5 (i)Air-fuel ratio : The air supplied per 100 moles of dry products is = 22.65 ...

532 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 Example 11.29. The exhaust from an engine running on benzole was measu ...

FUELS AND COMBUSTION 533 dharm \M-therm\Th11-2.pm5 X xyC 12 2 2 F + HG I KJ H + Y O 2 +^79 21 Y N 2 → 0.15CO 2 + 0.03CO + 0.03C ...

534 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 C 6 H 6 + 7.5O 2 → 6CO 2 + 3H 2 O (vapour) nR = 1 + 7.5 = 8.5, nP = 6 ...

FUELS AND COMBUSTION 535 dharm \M-therm\Th11-2.pm5 HEATING VALUES OF FUELS Example 11.34. The lower heating value of propane at ...

536 ENGINEERING THERMODYNAMICS dharm \M-therm\Th11-2.pm5 Given that the enthalpies of combustion at 25°C are : C 6 H 6 = – 31695 ...

FUELS AND COMBUSTION 537 dharm \M-therm\Th11-2.pm5 +Example 11.37. The higher heating value of kerosene at constant volume whose ...