TITLE.PM5

dharm \M-therm\Th15-3.pm5 818 ENGINEERING THERMODYNAMICS temperature difference between the two fluids remains more or less near ...

dharm \M-therm\Th15-3.pm5 HEAT TRANSFER 819 Design and constructional features On the basis of design and constructional featur ...

dharm \M-therm\Th15-3.pm5 820 ENGINEERING THERMODYNAMICS (iii)Multiple shell and tube passes. Multiple shell and tube passes are ...

dharm \M-therm\Th15-3.pm5 HEAT TRANSFER 821 Total heat transfer rate in the heat exchanger, Q = UA θm ...(15.48) Hot fluid Cold ...

dharm \M-therm\Th15-3.pm5 822 ENGINEERING THERMODYNAMICS and dtc = dQ mc dQ &cpccC = where, Ch = m&h cph = Heat capacity ...

dharm \M-therm\Th15-3.pm5 HEAT TRANSFER 823 Integrating between inlet and outlet conditions (i.e., from A = 0 to A = A), we get ...

dharm \M-therm\Th15-3.pm5 824 ENGINEERING THERMODYNAMICS Cold Cold Hot Annulus surrounding the pipe Pipe ( ) Flow arrangement.a ...

dharm \M-therm\Th15-3.pm5 HEAT TRANSFER 825 Substituting the values of 1 Ch and 1 Cc into eqn. (15.58), we get ln (θ 2 /θ 1 ) = ...

dharm \M-therm\Th15-3.pm5 826 ENGINEERING THERMODYNAMICS Solution. Given : m&h = 0.2 kg/s ; m&c = 0.5 kg/s ; th 1 = 75°C ...

dharm \M-therm\Th15-3.pm5 HEAT TRANSFER 827 or A = Q Uθm = × × 25 122 1000 325 29 12 . . = 2.65 m (^2). (Ans.) Example 15.19. In ...

dharm \M-therm\Th15-3.pm5 828 ENGINEERING THERMODYNAMICS = ()() ln [( ) / ( )] ()() ln [( ) / ( )] tt tt tt tt hc hc hc hc 12 2 ...

dharm \M-therm\Th15-3.pm5 HEAT TRANSFER 829 Overall heat transfer coefficient is given by 11 111 Uh d g dh h h o is g s =+ =+ as ...

dharm \M-therm\Th15-3.pm5 830 ENGINEERING THERMODYNAMICS 1250 × (0.9 × 2592) = m&c × 4.187 (47 – 24) ∴ m&c (= m&w) = ...

dharm \M-therm\Th15-3.pm5 HEAT TRANSFER 831 or L = 1009 1 0 0384 2 245 . . ~ π× × × − 17.1 m. (Ans.) Example 15.22. A feed water ...

dharm \M-therm\Th15-3.pm5 832 ENGINEERING THERMODYNAMICS or hi = k d× 0.023 (Re) 0.8 (Pr)0.33 ...(i) Re = ρ μ Vd= ×× × − 1000 0 ...

dharm \M-therm\Th15-3.pm5 HEAT TRANSFER 833 The energy which a radiating surface releases is not continuous but is in the form o ...

dharm \M-therm\Th15-3.pm5 834 ENGINEERING THERMODYNAMICS of radiation emitted per unit wavelength varies at different wavelength ...

HEAT TRANSFER 835 dharm \M-therm\Th15-4.pm5 Dividing both sides by G, we get G G G G G G G G art++= a + ρ + τ = 1 ...(15.67) whe ...

836 ENGINEERING THERMODYNAMICS dharm \M-therm\Th15-4.pm5 Gray body. If the radiative properties, α, ρ τ of a body are assumed to ...

HEAT TRANSFER 837 dharm \M-therm\Th15-4.pm5 where, Eb = Emissive power of a black body, and ...(15.69) σ = Stefan-Boltzmann cons ...