Microsoft Word - Cengel and Boles TOC _2-03-05_.doc

Chapter 5 | 235 STEAM V 2 = 900 ft/s P 2 = 200 psia T 1 = 700°F P 1 = 250 psia A 1 = 0.2 ft^2 m = 10 lbm/s qout = 1.2 Btu/lbm FI ...

236 | Thermodynamics Dividing by the mass flow rate m.and substituting, h 2 is determined to be Then, Discussion Note that the t ...

Chapter 5 | 237 AIR W ̇in =? T 2 = 400 K qout = 16 kJ/kg P 1 = 100 kPa P 2 = 600 kPa T 1 = 280 K m ̇ = 0.02 kg/s FIGURE 5–27 Sch ...

238 | Thermodynamics Analysis We take the turbineas the system. This is a control volumesince mass crosses the system boundary d ...

3 Throttling Valves Throttling valves are any kind of flow-restricting devicesthat cause a signif- icant pressure drop in the fl ...

Assumptions 1 Heat transfer from the tube is negligible. 2 Kinetic energy change of the refrigerant is negligible. Analysis A ca ...

Chapter 5 | 241 EXAMPLE 5–9 Mixing of Hot and Cold Waters in a Shower Consider an ordinary shower where hot water at 140°F is mi ...

4b Heat Exchangers As the name implies,heat exchangersare devices where two moving fluid streams exchange heat without mixing. H ...

at 25°C. Neglecting any pressure drops, determine (a) the mass flow rate of the cooling water required and (b) the heat transfer ...

Substituting, we find (b) To determine the heat transfer from the refrigerant to the water, we have to choose a control volume w ...

The velocities involved in pipe and duct flow are relatively low, and the kinetic energy changes are usually insignificant. This ...

Substituting the known quantities, the exit temperature of the air is deter- mined to be Discussion Note that heat loss from the ...

ple,mi0 if no mass enters the control volume during the process,me 0 if no mass leaves, and m 1 0 if the control volume is in ...

one of these with satisfactory results. The degree of satisfaction depends on the desired accuracy and the degree of validity of ...

Mass balance: Energy balance: Net energy transfer Change in internal, kinetic, by heat, work, and mass potential, etc., energies ...

250 | Thermodynamics m 1 = 1 kg Qin = 500 W System boundary Liquid Vapor H 2 O V = 6 L P = 75 kPa (gage) ̇ FIGURE 5–49 Schematic ...

Chapter 5 | 251 (b) Noting that the microscopic energies of flowing and nonflowing fluids are represented by enthalpy hand inter ...

252 | Thermodynamics Thus, and Therefore, after 30 min there is 0.6 kg water (liquid vapor) left in the pressure cooker. Discus ...

by the normal and shear components of viscous forces on the control surface, and Wotheris the work done by other forces such as ...

energy per unit mass e, which is euke pe uV^2 /2 gz(Fig. 5–53). This yields (5–54) Substituting the left-hand side of Eq. ...