Handbook of Civil Engineering Calculations

ond column, and total them. This column contains full information concerning the sam- pling distribution of the mean. Thus, sinc ...

FIGURE 23. Sampling distribution of the mean. becomes P(1.841 < /x < 1.871) = 0.95. Thus, there is a 95 percent probabilit ...

that under the present method. Thus, the hypotheses are // 0 : JJL = 3.50 h and a = 0.64 h; H 1 IfJL <3.50h. Compute the pro ...

gions are labeled as shown. The values of X and z at the boundary of the acceptance and rejection regions are called the critica ...

Related Calculations: If the null hypothesis is accepted when, in fact, it is false, a Type II error has been committed, and the ...

variable; then P and p are also continuous. Since the sample is very large, the sampling distribution ofp is approximately norma ...

Calculation Procedure: Compute the true properties of the sampling distribution of the proportion Apply Eqs. a and c of the pre ...

FIGURE 27. System with components in series. components, C 1 and C 2 , and let the subscripts 1, 2, and S refer to C 1 , C 2 , a ...

Calculation Procedure: Compute the probability that a particular satellite will survive the first year Refer to the earlier cal ...

CORRESPONDENCE BETWEEN POISSON FAILURE AND NEGATIVE-EXPONENTIAL LIFE SPAN The failure of a certain type of device has a Poisson ...

SYSTEM WITH COMPONENTS IN SERIES A system consists of three type A components and two type B components, all arranged in series. ...

that the system will be operating at the expiration of 60 days as a result of each of the fol- lowing causes: (a) only one compo ...

ANALYSIS OF COMPOSITE SYSTEM BY CONVENTIONAL METHOD A system is constructed by arranging the components in the manner shown in F ...

system, and one that combines series and parallel arrangements is a composite system. A composite system may be regarded as comp ...

C 4 = 241,570(0.17) = 41,067. Thus, the number of particles that reach d by way OfC 1 , C 2 , and either C 3 or C 4 = 42,630 + 4 ...

fails to traverse the system if it fails to penetrate C 6. From Fig. 32, the number of such particles is 723,879 - 217,164 = 506 ...

Compute the probability of a type 1 failure To simplify the notation, let R = reliability of a component, with a subscript iden ...

FIGURE 34 178,600, and the number that fail to penetrate C 4 = 291,400 - 113,646 = 177,754. These particles return to a in Fig. ...

OPTIMAL INVENTORY TO MEET FLUCTUATING DEMAND A firm sells a commodity that is used only during the winter. Because the commodity ...

TABLE 29. Values of P Number of units demanded Y Number of units ordered^ 150 160 170 180 190 200 150 3750 3710 3670 3630 3590 3 ...