Mechanical Engineering Principles
132 MECHANICAL ENGINEERING PRINCIPLES 5 revolutions=5 rev×^2 πrad 1 rev = 10 πrad From equation (11.17),ω^22 =ω^21 + 2 αθ i.e. ( ...
LINEAR AND ANGULAR MOTION 133 S 0 N W E 0 100 200 300 300 m/s 200 m/s Scale : velocity in m/s 22 ° 22 ° 30 ° ab b ba a Figure 11 ...
134 MECHANICAL ENGINEERING PRINCIPLES A vector diagram depicting the motion of the crane and load is shown in Figure 11.5.oarepr ...
LINEAR AND ANGULAR MOTION 135 A point on a wheel has a constant angu- lar velocity of 3 rad/s. The angle turned through in 15 s ...
12 Linear momentum and impulse At the end of this chapter you should be able to: define momentum and state its unit state Newto ...
LINEAR MOMENTUM AND IMPULSE 137 30 m/s= 30 × 3 .6km/h =108 km/h=velocity of cricket ball. Problem 3. Determine the momentum of a ...
138 MECHANICAL ENGINEERING PRINCIPLES from which,common velocity,v= 0. 30 0. 050 = 6 m/s in the direction that the 30 g mass is ...
LINEAR MOMENTUM AND IMPULSE 139 Calculate the momentum of a car of mass 750 kg moving at a constant veloc- ity of 108 km/h. [22 ...
140 MECHANICAL ENGINEERING PRINCIPLES Problem 8. The average force exerted on the workpiece of a press-tool operation is 150 kN, ...
LINEAR MOMENTUM AND IMPULSE 141 Massm=40 g= 0 .040 kg, initial velocity, u=15 m/s and final velocity,v=−5 m/s (nega- tive since ...
142 MECHANICAL ENGINEERING PRINCIPLES (c) Resistive force of ground=mass×accelera- tion. The acceleration is determined using v^ ...
LINEAR MOMENTUM AND IMPULSE 143 Exercise 61 Short answer questions on lin- ear momentum and impulse Define momentum. State Newt ...
13 Force, mass and acceleration At the end of this chapter you should be able to: define force and state its unit appreciate ‘g ...
FORCE, MASS AND ACCELERATION 145 Thus, forceαacceleration, or force=a constant× acceleration, this constant of proportionality b ...
146 MECHANICAL ENGINEERING PRINCIPLES The weight of an object is the force acting vertically downwards due to the force of gravi ...
FORCE, MASS AND ACCELERATION 147 Now try the following exercise Exercise 63 Further problems on New- ton’s laws of motion (Takeg ...
148 MECHANICAL ENGINEERING PRINCIPLES Sinceθ=ωt,then t= θ ω ( 13. 2 ) Dividing (13.1) by (13.2) gives: V t = 2 vsin θ 2 θ ω = vω ...
FORCE, MASS AND ACCELERATION 149 constant at 34 km/h, determine the change in acceleration when leaving one arc and entering the ...
150 MECHANICAL ENGINEERING PRINCIPLES Some typical values of mass and the radius of gyration are given in Table 13.1, where A=cr ...
FORCE, MASS AND ACCELERATION 151 State Newton’s second law of motion. Define the Newton. State Newton’s third law of motion. Ex ...
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