Mechanical Engineering Principles

172 MECHANICAL ENGINEERING PRINCIPLES can be transmitted, and (b) maximum force which can be transmitted when the belt is runnin ...

FRICTION 173 15.4 Friction on an inclined plane Angle of repose Consider a massmlying on an inclined plane, as shown in Figure 1 ...

174 MECHANICAL ENGINEERING PRINCIPLES For limiting friction, F=μN ( 15. 5 ) From equations (15.3) to (15.5), solutions of proble ...

FRICTION 175 plane is so much smaller than to move the body up the plane. 15.7 Motion up a plane due to a horizontal forceP This ...

176 MECHANICAL ENGINEERING PRINCIPLES q q P P sin q P cos q Figure 15.11 The components formg are shown by the phasor diagram of ...

FRICTION 177 Now try the following exercise Exercise 76 Further problems on friction on an inclined plane Where necessary, takeg ...

178 MECHANICAL ENGINEERING PRINCIPLES pd D 1 D 2 p q Figure 15.15 as shown in Figure 15.15, and d= (D 1 +D 2 ) 2 Ifμis the coeff ...

FRICTION 179 Efficiencyη = useful work done actual work done which is usually expressed as a percentage i.e. η= Wp W(μπd+p)×πd ( ...

180 MECHANICAL ENGINEERING PRINCIPLES The coefficient of friction should have a .........value for materials concerned with bra ...

FRICTION 181 to maintain a constant speed of sliding is: (a) 100.4 N (b) 40 N (c) 99.6 N (d) 250 N The normal force between two ...

16 Motion in a circle At the end of this chapter you should be able to: understand centripetal force understand D’Alembert’s pr ...

MOTION IN A CIRCLE 183 h=vertical distance of the centre of gravity of the car from the ground, L=distance between the centre of ...

184 MECHANICAL ENGINEERING PRINCIPLES a 2 a 2 a 1 T 2 T 1 F 1 F 2 R 2 R 1 (a) (b) Figure 16.3 16.2 Motion on a curved banked tra ...

MOTION IN A CIRCLE 185 Problem 4. What angle of banking of the rails is required for Problem 3 above, for the outer rail to have ...

186 MECHANICAL ENGINEERING PRINCIPLES Equating equations (16.12) and (16.13) gives: mω^2 r sinθ = mg cosθ Rearranging gives: mω^ ...

MOTION IN A CIRCLE 187 However, 1 kg m/s^2 =1 N, hence,tension in the string,T=15 N From equation (16.13), T= mg cosθ from which ...

188 MECHANICAL ENGINEERING PRINCIPLES AtB,T= 0 Thus, weight=centrifugal force atB, or mg= mvB^2 r from which, v^2 B=gr ( 16. 22 ...

MOTION IN A CIRCLE 189 and v 2 = √ 4 gr= √ 4 × 9. 81 × 0. 6 = 4 .852 m/s Resolving forces in a direction along the string, T =te ...

190 MECHANICAL ENGINEERING PRINCIPLES What is the potential energy at the top of a circle for the motion in a vertical circle? ...

17 Simple harmonic motion At the end of this chapter you should be able to: understand simple harmonic motion determine natural ...