Handbook of Civil Engineering Calculations

The most difficult beaches to clean are those comprised of gravel, pebbles, or small boulders. Two reasons for this are: (1) the ...

SECTION 5 SURVEYING, ROUTE DESIGN, AND HIGHWAY BRIDGES SURVEYING AND ROUTE DESIGN Plotting a Closed Traverse Area of Tract with ...

Surveying and Route Design PLOTTING A CLOSED TRAVERSE Complete the following table for a closed traverse. Course Bearing Length, ...

In Fig. 2, draw the known courses a, c, and e. Then introduce the hypothetical course/ to form a closed traverse. Calculate the ...

AREA OF TRACT WITH RECTILINEAR BOUNDARIES The balanced latitudes and departures of a closed transit-and-tape traverse are record ...

Establish the DMD of each course by successive applications of Eq. 3 Thus, DMDDE - 143.6 ft (43.77 m); DMD^ = 143.6 + 143.6 + 2 ...

FIGURES FIGURE 6. Partition of tract. DMDEC = 143.6 + 143.6 + 54.9 = 342.1 ft (104.27 m); DMDCD = 342.1 + 54.9 - 198.5 = 198.5 f ...

By Eq. 4, 7602 =^1 / 2 GC(265.5 sin 108°59.6'); solving gives GC = 60.6 ft (18.47 m). By Eq. 5, tan EGC = 265.5 sin 108°59.6V(60 ...

28.5(110 - 75)] = 6590 ft 2 (612.2 m 2 ). Hence, both equations yield the same result. The second equation has a distinct advant ...

Apply Eqs. 8 and 9 successively to obtain the elevations recorded in the accompany- ing table. Point BS, ft(m) HI, ft(m) FS, ft( ...

H = Ks COS^2 Ct + C cos a (11) V=y 2 Kssm2a + Csma (12) Elevation of N= elevation of O + OM + V-NQ (13) where K = stadia interva ...

FIGURE 10 where Am = area of center section. Compute Am. Note that each coordinate of the center section of a prismoid is the ar ...

ephemeris, it was found that the declination of the sun at the instant of observation was 7°58'N. What was the azimuth of the su ...

ured along the celestial equator; and the declination, which is the angular distance of the body from the celestial equator as m ...

TfME OF CULMINATION OFA STAR Determine the Eastern Standard Time (75th meridian time) of the upper culmination of Polaris at a s ...

long chord, middle ordinate, and external distance, (b) Determine all the data necessary to stake the curve if the chord distanc ...

And, M = ^(I-COs 1 X 2 A) (21) M = 1200(1 - 0.9703) = 35.6 ft (10.85 m) Lastly, E = R tan^1 X 2 A tan^1 X 2 A (22) E= 1200(0.249 ...

Calculate the degree of curve in the present instance Part c. Since the subtended central angle is directly proportional to its ...

AOP = 180° - (118° + 21°27.7') = 40°32.3' arc AP = 2ir (800)(40°32.3')/360° = 566.0 ft (172.52 m); station of P = (22 + 00) + (5 ...

FIGURE 16. Compound curve. and 800 ft (243.8 m), as shown in Fig. 16. The minimum allowable radius is 1000 ft (304.8 m). Compute ...