The Foundations of Chemistry

Exercises 395 0 40.What does “base strength” mean? What does “acid strength” mean? 0 41.Classify each of the following substance ...

396 CHAPTER 10: Reactions in Aqueous Solutions I: Acids, Bases, and Salts Acidic and Basic Salts 0 65.What are polyprotic acids? ...

Exercises 397 (b) To which atom is the H of the product bonded? How is the H bonded? Preparation of Acids 0 83.A volatile acid s ...

398 CHAPTER 10: Reactions in Aqueous Solutions I: Acids, Bases, and Salts or ions. The larger, lighter circles represent the ani ...

11 Reactions in Aqueous Solutions II: Calculations ...

OUTLINE Aqueous Acid–Base Reactions 11-1 Calculations Involving Molarity 11-2 Titrations 11-3 The Mole Method and Molarity 11-4 ...

CALCULATIONS INVOLVING MOLARITY In Sections 3-6 through 3-8 we introduced methods for expressing concentrations of solu- tions a ...

We often express the volume of a solution in milliliters rather than in liters. Likewise, we may express the amount of solute in ...

Because two solutes are present in the solution after reaction, we must calculate the concen- trations of both. _?_ 0.10 MHCl ...

 mL C so a l ( n OH) 2  88n  mmo p l re C s a e ( n O t H) 2  88n  mm ne o e l d H ed Cl  88n  mL ne H ed C e l d (aq)  ...

The reaction produces 100. mmol of potassium sulfate. This is contained in 300. mL of solu- tion, and so the concentration is _? ...

Titration is the process in which a solution of one reactant, the titrant, is carefully added to a solution of another reactant, ...

_?_ mol HCl10.2 mmol NaOH10.2 mmol HCl We know the volume of the HCl solution, so we can calculate its molarity. 0.278 MHCl ...

Because the reaction ratio is two millimoles of NaOH to one millimole of H 2 SO 4 , the H 2 SO 4 solution must contain 5.10 mill ...

EXAMPLE 11-7 Standardization of an Acid Solution Calculate the molarity of a solution of H 2 SO 4 if 40.0 mL of the solution neu ...

Plan We first write the balanced equation for the reaction between NaOH and KHP. We then calcu- late the number of moles of NaOH ...

_?_ g (COOH) 2 0.003550 mol NaOH 0.1598 g (COOH) 2 The 0.1743-g sample contained 0.1598 g of (COOH) 2 , so its percentage pu ...

Sulfuric acid is a diprotic acid. One molecule of H 2 SO 4 can furnish 2H
ions. H 2 O H 2 SO 4 8888n 2H
(aq)
SO 42 (aq) 1 mol ...

Solution N _?_ 0.111 NHNO 3 MHNO 3 Because normality is equal to molarity times the number of equivalents per mole of solut ...

Similar relationships can be written for a solution of a base. Because 1 eq of acid always reacts with 1 eq of base, we may writ ...