The Foundations of Chemistry

Solution First we calculate the number of equivalents of Na 2 CO 3 in the sample. no. eq Na 2 CO 3 0.364 g Na 2 CO 3 6.87 10 ...

and (2) the change-in-oxidation-number method. Many redox equations can be balanced by simple inspection, but you should master ...

Solution I 2
S 2 O 32 88nI
S 4 O 62  I 2 88nI (red. half-reaction) I 2 88n 2I I 2
2 e 88n2I (balanced red. half-reacti ...

When balancing redox equations, we often find it convenient to omit the spectator ions (Section 4-3) so that we can focus on the ...

Solution Total ionic equation 10[Fe^2
(aq)
SO 42 (aq)]
2[K
(aq)
MnO 4 (aq)]
8[2H
(aq)
SO 42 (aq)]88n 5[2Fe^3
(aq)
3SO 42 ( ...

The oxidation half-reaction involves three electrons, and the reduction half-reaction involves two electrons. We balance the ele ...

4.Insert coefficients into the equation to make the total increase and decrease in oxida- tion numbers equal. 5.Balance the othe ...

5 0
2
2 8 n 888888 888n 888888 8888888888888888888888888 8888888888 0
1
3 0 H
(aq)
NO 3 (aq)
Cu(s)88nCu^2
(aq)
NO(g) ...

Aluminum is oxidized; it is the reducing agent. H 2 O is reduced; it is the oxidizing agent. OH
H 2 O
Al88n[Al(OH) 4 ]
H 2
3 ...

We see that ethanol is oxidized; it is the reducing agent. Cr 2 O 72 ions are reduced; they are the oxidizing agent. H

C 2 H 5 ...

STOICHIOMETRY OF REDOX REACTIONS One method of analyzing samples quantitatively for the presence of oxidizableor reducible subst ...

Solution The reaction ratio is MnO 4 (aq)
8H
(aq)
5Fe^2
(aq)88n5Fe^3
(aq)
Mn^2
(aq)
4H 2 O(
) rxn ratio: 1 mol 5 mol The num ...

and Na 2 SO 3 is the usual source of SO 32 ions. Thus, the preceding reaction ratio could also be expressed as 1 mol K 2 Cr 2 O ...

428 CHAPTER 11: Reactions in Aqueous Solutions II: Calculations Exercises Molarity *01.Why can we describe molarity as a “method ...

Exercises 429 Standardization and Acid–Base Titrations: Mole Method *23.Define and illustrate the following terms clearly and co ...

430 CHAPTER 11: Reactions in Aqueous Solutions II: Calculations 17.62 mL of a standardized 0.1060 Nsolution of NaOH. (a) What is ...

Exercises 431 *63.Write the balanced net ionic equations for the reactions given. Then, using the reactants shown in parentheses ...

432 CHAPTER 11: Reactions in Aqueous Solutions II: Calculations *86.Find the volume of 0.250 MHI solution required to titrate (a ...

12 Gases and the Kinetic–Molecular Theory ...

OUTLINE 12-1 Comparison of Solids, Liquids, and Gases 12-2 Composition of the Atmosphere and Some Common Properties of Gases 12- ...