BioPHYSICAL chemistry
9-fold symmetry around a central symmetry axis. Associated with each pair of subunits are three bacteriochlorophylls and one car ...
these molecules. In the photosynthetic membrane, the energy is trans- ferred in 3 ps to a second protein called the light-harves ...
(which have the structure of bacteriochlorophyll without the central Mg), two quinones, and one nonheme iron. Spectroscopic stud ...
with the 865-nm absorption band, was the primary electron donor, now termed P865. The two quinones could be biochemically remove ...
(20.4) Electron transfer proceeds rapidly from the excited state to a bacterio- chlorophyll monomer in 3 ps, and a bacteriopheop ...
with the nonheme iron located directly on the symmetry axis. The bacteriochlorophyll monomer and bacteriopheophytin that serve a ...
30 ps, because the excitation energy is not trapped on P700 but can be trapped on one of the many chlorophylls. Electron transfe ...
The site of water oxidation is photosystem II, or the water-oxidation complex. To oxidize water to molecular oxygen, the protein ...
432 PART 3 UNDERSTANDING BIOLOGICAL SYSTEMS USING PHYSICAL CHEMISTRY Primary and secondary quinone electron acceptors and nonhem ...
complex, the resolution limit was limited and the three-dimensional struc- ture of photosystem II could not be determined in det ...
Third, the generation of electrons is sequen- tial as each absorption of a photon results in the transfer of a single electron. ...
between two manganese atoms, other than the bridged manganese. In addition, a peak at 3.4 Å was assigned as representing a manga ...
The hydrogen-abstraction model was highly innovative but appears to be somewhat over-simplified compared to the actual mechanism ...
Problems 20.1 Plants make chlorophyll whereas bacteria synthesize bacteriochlorophyll. What are the differences between these mo ...
20.10 Based upon the S cycle, what is the maximum rate of oxygen production possible in plants? 20.11 Why does P680 have a high ...
CHAPTER 1 1.1 =0.981 Pa =0.0981 Pa 1.2 Pinitial=Pfinal(Vfinal/Vinitial) =(6 atm)(2 L/4 L) =3 atm 1.3 (a) (b) 1.4 Temperature (K) ...
1.6 =0.9711 atm −0.00576 atm =0.965 atm 1.7 1.8 1.9 1.10 Since the total is 3.45 mol, and the total pressure is 1 atm, the parti ...
1.14 Amino acids have the fundamental unit of a carbonyl group and an amino group bonded to a carbon atom. 1.15 There are 20 dif ...
2.5 The ITC profile reflects the binding of the drug to the target. 2.6 A favorable drug candidate would have an ITC profile tha ...
2.14q=nCVΔT =(1.5 mol)(25 J/(Kmol))(35 K) =1.31 J Since there is no work performed, the heat equals the change in internal energ ...
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