BioPHYSICAL chemistry
11.15 The term in the left parentheses is: so the term on the right-hand side must be zero, yielding 11.16 (a) (b) 11.17 If B &l ...
11.19 11.20 ψ 1 (y) =N 1 (2y)e−y (^2) /2 11.21 (a) (b)V(x) is continuous at L/2. a L b L cL ab c 22 2 48 48 + ⎛ ⎝ ⎜⎜ ⎞ ⎠ ⎟⎟=+=or ...
(c) (d) The region beyond L/2 is classically forbidden and so the probability of finding the particle in this region is very sma ...
12.5 12.6 12.7 Principal, n=1, 2, 3,...; angular momentum, l=0, 1, 2,..., n−1; magnetic ml=l, l−1, l−2,... , −l. 12.8 12.9 n, Qu ...
12.14 12.15 The limits are r=1.058 or x=2 and infinity so the probability is equal to: 0 −(−e−^4 (2 × 42 + 2 × 4 +1)) =0.75 12.1 ...
12.19 A wavefunction can have a node where the value is exactly equal to zero. For the 2s orbital this occurs at: 12.20Φ(φ+ 2 π) ...
12.24 The boundary surface represents the 90% probability value. 12.25Angular momentum must be conserved and photons carry angul ...
12.34 The placement of the outer electron for boron in a 2p orbital com- pared to the 2s orbital for beryllium results in a lowe ...
13.7 An increase in coupling will increase the energy difference between the molecular orbitals. 13.8 In valence bond theory, a ...
CHAPTER 14 14.1 A=εcl where the proportionality constant εis the molar absorption co- efficient, or extinction coefficient, the ...
14.10Since the photon carries a spin of 1, the angular momentum of the electron must change by 1 to conserve momentum. 14.11 Onl ...
CHAPTER 15 15.1 To resolve the atomic structure the wavelength must be ≈1Å. 15.2 X-ray microscopes cannot be constructed because ...
15.11 Amino acids forming proteins are only of one isomer; the other is never present. In contrast, both isomers are often prese ...
16.2 16.3 16.4 Large chemical shifts usually arise from small shielding and low electron density. 16.5 Large chemical shifts usu ...
16.17MRI is a non-invasive technique for showing the presence of fluids. For an accident, MRI would show the build-up of fluids ...
16.27 The oxidation state determines whether there are five or six elec- trons in the d orbitals. The five electronic levels are ...
17.7 The initial three-dimensional crystals were not suitable for X-ray diffraction but the two-dimensional crystals yield usefu ...
the optical nerve. In addition to questions concerning the response mechanism, the reason why why vertebrates respond to blue li ...
18.7 =−12.3 +5.8 kJ mol−^1 =−6.5 kJ mol−^1 =9.6 −5.8 kJ mol−^1 =+3.8 kJ mol−^1 ΔGNET=ΔGNa+ΔGK=−2.7 kJ mol−^1 18.8 (a) =10.0 kJ m ...
18.10 =−12.3 −5.8 kJ mol−^1 =−18.1 kJ mol−^1 =9.6 +5.8 kJ mol−^1 =15.4 kJ mol−^1 ΔGNET=ΔGNa+ΔGK=−2.7 kJ mol−^1 18.11 Transporter ...
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