2018-10-01_Physics_For_You
ALTERNATING CURRENT It is the current which varies continuously in magnitude and periodically in direction. It can be represente ...
L dI dt =ε 0 sinωt ...(iii) Integration of this expression gives the current as a function of time I L tdt L L==∫ −+tC ε ω ε ω ( ...
Vector Analysis (Phasor Algebra) e complex quantities normally employed in ac circuit analysis, can be added and subtracted lik ...
Resonance Condition : e current will be maximum when ω ω L C −= 1 0 ⇒=ω 1 LC and corresponding frequency is υ ω ππ == 2 1 2 1 ...
1 Z is known as admittance (Y). erefore, Y Z RjL RL == jC − + + 1 222 ω ω ω = ++− + RjCR LC L RL ()ωωω ω 232 222 Resonance Con ...
CURRENT ELECTRICITY ELECTRIC CURRENT KIRCHHOFF’S LAW COMBINATION OF RESISTANCE AND ELECTRICAL POWER ELECTRICAL RESISTANCE OHM’S ...
A coil of inductance 8.4 mH and resistance 6 : is connected to a 12 V battery. e current in the coil is 1.0 A at approximately ...
A simple LR circuit is connected to a battery at time t = 0. e energy stored in the inductor reaches half its maximum value at ...
SOLUTIONS (d) : i = ε R e Rt 1 − L − ; i = 12 6 1 6 V 84103 Ω − − × ...
M = φ i M a R = μ 0 2 272 / = μ 0 2 2 2 a p/R ? p = 7 (a) : C^1 L L Þ C 2 C+^12 C We know that q = qm cos Zt i = qmZ cos ωt ...
zero and that due to capacitance 1 ωC becomes innite, so equivalent circuit is shown in gure. R/ 2 R/ 2 R R K EE r 1 ...
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Two positive point charges each of magnitude 10 C are xed at positions A and B at separation 2 d = 6m. A negatively charged pa ...
A particle of charge –16 × 10–18 C moving with velocity 10 m s–1 along the X-axis enters a region where a magnetic eld of indu ...
SOLUTIONS (b) : Net force on – q towards the centre. F = (2F 1 ·sinq) = × + (^222) 22 . KQq dR R dR For particle to move i ...
e solution of this equation is Q = Q 0 sin (Zt + φ), where t = 0, Q = Q 0 QCV CC CC 0 eq^12 V 12 == + = ×× × × − − 8210 20 10 1 ...
SECTION A Is the speed of light in glass independent of the colour of light? If not, which of the two colours; red and violet, ...
angle of refraction at A if refractive index of the material of the sphere is 3. Air A B C Air 60° (b) When red light passing th ...
(ii) express the velocity of propagation in terms of the amplitudes of the oscillating electric and magnetic elds. (b) How do y ...
respect to the pass axis of P 1. A monochromatic source S of unpolarised light of intensity I 0 is kept in front of the polaroid ...
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